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Alja [10]
2 years ago
11

15 tan^3x=5tanx,(0,2pi)

Mathematics
1 answer:
Sauron [17]2 years ago
4 0

Answer:

steps below

Step-by-step explanation:

15 tan³x=5tanx     .... (0,2π)

5tanx(3tan²x - 1) = 0

tanx = 0            <u>x = π</u>  (0° is excluded)

or 3tan²x - 1 = 0

(√3 tanx + 1) (√3 tanx - 1) = 0

tanx = 1 /√3      <u>x = π/6 (30°)    or    x = 5π/6  (150°)</u>

tanx = - 1 /√3      <u>x = 7π/6 (210°)    or    x = 11π/6  (330°)</u>

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Step-by-step explanation:

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Answer

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Answer;

C) The second arc should be centered at C.

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3 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

Previous concepts and notation

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H1: \sigma >0.027

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p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

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b. between .025 and .05

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