Answer: B- A(n) = P+(n-1)i•P, where n is a positive integer
Step-by-step explanation:
To get the equation of the line, you need two points that belong to this line.
From the given graph, we can choose any two points: (0,-4) and (-2,0)
The general for of the linear straight line is:
y = mx + c where m is the slope and c is the y-intercept
First, we will calculate the slope using the following rule:
slope = (y2-y1) / (x2-x1)
slope (m) = (0--4) / (-2-0) = 4/-2 = -2
The equation of the line now is: y = -2x + c
Then, we will get the value of the c. To do so, we will choose any point and substitute in the equation. I will choose the point (0,-4)
y = -2x + c
-4 = -2(0) + c
c = -4
Based on the above calculations, the equation of the line is:
y = -2x - 4
Answer:
c
Step-by-step explanation:
1 + tan²theta = sec²theta
tan²theta = 3² - 1
tan²theta = 8
tan theta = sqrt(8)
Positive because Quadrant 1
sqrt(8) = sqrt(4×2) = sqrt(4)×sqrt(2)
= 2×sqrt(2)
Answer:
12 cm
Step-by-step explanation:
The square of the length of the tangent segment is equal to the product of near and far distances to the circle from the point of intersection of the secant and tangent:
(8 cm)^2 = (4 cm)(4 cm +x)
16 cm = 4 cm +x . . . . . . divide by 4 cm
12 cm = x . . . . . . . . . . . . subtract 4 cm
