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ollegr [7]
2 years ago
12

Simplify:(ay86.5x - 25 30 - 6x​

Mathematics
2 answers:
maw [93]2 years ago
6 0

Answer:

-x - 2530

Step-by-step explanation:

5x - 2530 - 6x

5x - 6x = -x

-x - 2530

Yanka [14]2 years ago
4 0

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    5/x-(25/30)=0  

Step by step solution :

STEP

1

:

           5

Simplify   —

           6

Equation at the end of step

1

:

 5    5

 — -  —  = 0  

 x    6

STEP

2

:

           5

Simplify   —

           x

Equation at the end of step

2

:

 5    5

 — -  —  = 0  

 x    6

STEP

3

:

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       x  

     The right denominator is :       6  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

2 0 1 1

3 0 1 1

Product of all  

Prime Factors  1 6 6

                 Number of times each Algebraic Factor

           appears in the factorization of:

   Algebraic    

   Factor      Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

x  1 0 1

     Least Common Multiple:   6x

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 6

  Right_M = L.C.M / R_Deno = x

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      5 • 6

  ——————————————————  =   —————

        L.C.M              6x  

  R. Mult. • R. Num.      5 • x

  ——————————————————  =   —————

        L.C.M              6x  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

5 • 6 - (5 • x)     30 - 5x

———————————————  =  ———————

      6x              6x    

STEP

4

:

Pulling out like terms :

4.1     Pull out like factors :

  30 - 5x  =   -5 • (x - 6)  

Equation at the end of step

4

:

 -5 • (x - 6)

 ————————————  = 0  

      6x      

STEP

5

:

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -5•(x-6)

 ———————— • 6x = 0 • 6x

    6x    

Now, on the left hand side, the  6x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -5  •  (x-6)  = 0

Equations which are never true:

5.2      Solve :    -5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

5.3      Solve  :    x-6 = 0  

Add  6  to both sides of the equation :  

                     x = 6

One solution was found :

x = 6

this should make it ez for you now

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morpeh [17]

Answer:

Below

Step-by-step explanation:

● cos O = 2/3

We khow that:

● cos^2(O) + sin^2(O) =1

So : sin^2 (O)= 1-cos^2(O)

● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9

● sin O = √(5)/3 or sin O = -√(5)/3

So we deduce that tan O will have two values since we don't khow the size of O.

■■■■■■■■■■■■■■■■■■■■■■■■■

●Tan (O) = sin(O)/cos(O)

● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)

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4 0
3 years ago
What is the length (magnitude) of the vector (2,-1)?
KiRa [710]

Answer:

\[\sqrt{5}\]

Step-by-step explanation:

The given vector is represented by (2,-1).

This can be represented in general form as (x,y) where x=2 and y=-1.

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Evaluating for the given values of x and y,

\[\sqrt{2^{2}+(-1)^{2}}\]\[=\sqrt{4+1}\]

\[=\sqrt{5}\]

Length of the vector is \[\sqrt{5}\]

5 0
2 years ago
3x - 2y + 3z = -20<br> 4x - 3y - 2z = 7<br> -5x + 5y + z = 9
skelet666 [1.2K]

Answer:

x= 4 y= 7 z= -6

Step-by-step explanation:

solve for one and you get them all

First, I got rid of the z by multiplying common factors (multiplied z by 2) and added equations 2 and 3 together after multiplying by 2

4x - 3y - 2z = 7

-10x+10y+2z= 18

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Then multiplied z by -3 (to get rid of the z) with the original equation 3

3x - 2y + 3z = -20

15x-15y-3z= -27

18x-17y= -47

Next find common thing between the 2 equations we got and multiply it by that and combine (we can multiply first equation by 3 to get rid of the x and solve for y)

-18x+21y= 75

18x-17y= -47

y=7

Work backwards, substitute 7 into the above equation, you get x= 4 and then same for z to get z= -6

8 0
2 years ago
Use slope-intercept form, y = mx + b to find the equation of the line that passes through the points (−6, 1) and (3, 4).
Mnenie [13.5K]

Answer:

y = one-third x + 3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

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Step 1: Find slope <em>m</em>

m = (4 - 1)/(3 + 6)

m = 3/9

m = 1/3

y = 1/3x + b

Step 2: Find <em>b</em>

4 = 1/3(3) + b

4 = 1 + b

b = 3

Step 3: Rewrite

y = 1/3x + 3

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