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Georgia [21]
2 years ago
12

At Southside Middle School, 20% of the students play an instrument. There are 305 students. How many students play an instrument

?
20 students
61 students
244 students
285 students

and don't just give the answer, actually explain
Mathematics
2 answers:
RoseWind [281]2 years ago
4 0

Answer:

61 Students.

Step-by-step explanation:

So you need to find 20% of 305. You can do this by dividing by 5.

305 divided by 5 equals 61.

If you have questions, ask please :)

masya89 [10]2 years ago
3 0

Answer:

61

Step-by-step explanation:

20 x 305 = 6,100

6,100/100 = <u>61</u>

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Answer:  The required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

Step-by-step explanation:  We are given that the set A has 48 elements and the set B has 21 elements.

(a) To determine the maximum possible number of elements in A ∪ B.

If the sets A and B are disjoint, that is they do not have any common element. Then, A ∩ B = { }   ⇒   n(A ∩ B) = 0.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-0=69.

So, the maximum possible number of elements in  A ∪ B is 69.

(b) To determine the minimum possible number of elements in A ∪ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then,  n(A ∩ B) = 21.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-21=48.

So, the minimum possible number of elements in  A ∪ B is 21.

(c) To determine the maximum possible number of elements in A ∩ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then, n(A ∩ B) = 21.

So, the maximum possible number of elements in  A ∩ B is 21.

(d) To determine the minimum possible number of elements in A ∩ B.

If the sets A and B are disjoint, that is there is no common element in the sets A and B . Then,  n(A ∩ B) = 0.

So, the maximum possible number of elements in  A ∩ B is 0.

Thus, the required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

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Veseljchak [2.6K]

SOLUTION

In this question, we are meant to expand the expression:

(10x+1)^{3\text{ }}\text{ = ( 10 x + 1 ) (10 x + 1 ) ( 10 x + 1 )}\begin{gathered} (10x+1)(10x+1)=100^{}x^2\text{ + 20 x + 1} \\ \text{Then,} \\ (100x^2+20x+1)(10x+1)=1000x^{3\text{ }}+200x^2+10x+100x^2\text{ + 20 x + 1} \\ \text{ = 1000 x}^{3\text{ }}\text{ + }300x^2\text{ + 30 x + 1} \\  \\ \text{CONCLUSION: ( 10 x + 1 )}^{3\text{ }}=1000x^{3\text{ }}+300x^2\text{ + 30 x +1} \end{gathered}

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Step-by-step explanation:

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Step-by-step explanation:

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