I need help on 11 please

Mathematics

1 answer:

Alisiya [41]3 years ago

5 0

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Question 11 :

the equations are :

$- 2x - 3y = 9$

$4x + 6y = - 18$

now, let's graph the lines ~

As you can see in the attachment, The lines coincides each other, so the equations are :

consistent and dependent

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The volume of a sphere is 1928pi m^3. what is the surface area of the sphere to the nears tenth

nika2105 [10]

$\bf \begin{array}{llll}
\textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\\
----------\\
\textit{surface area of a sphere}\\\\
S=4\pi r^2
\end{array}\qquad r=radius\\\\
-----------------------------\\\\
V=1928\implies 1928=\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 1928}{4\pi }=r^3
\\\\\\
\sqrt[3]{\cfrac{3\cdot 1928}{4\pi }}=\boxed{r}\qquad thus
\\\\\\
S=4\pi \left( \boxed{\sqrt[3]{\cfrac{3\cdot 1928}{4\pi }}} \right)^2$