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Dmitrij [34]
3 years ago
5

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20

meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. [beep] A single lap should be completed each time you hear this sound. [ding] Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over. The test will begin on the word start. On your mark, get ready, start.
Mathematics
2 answers:
netineya [11]3 years ago
7 0

Answer:

belt gvcgvguguvycyvfytfrddrdrgccgcvvhuhib

Arturiano [62]3 years ago
7 0

Answer:

Don't take up the space, other people have important questions but you are being a nuisance to the program.

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I need help on the math question look at pic​
frutty [35]

Answer:

9 is answer . . . . . . . ........

5 0
3 years ago
What is three-fourths of 1,968
lara31 [8.8K]
All you have to so is divide 1968 by 4.

1968 ÷ 4 = 496.5 = 1/4


Now multiply 496.5 by 3 =  1, 489.5 = 3/4


I hope this helps! :_
7 0
3 years ago
Read 2 more answers
here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa
lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

0.75k=5 \iff k=6.\bar{6}

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

0.25k=5 \iff k=20

So, there would be 20 bricks in a 5 feet tall stack.

Finally, a coin is about 0.006 feet, which leads to

0.006k=5 \iff k=833.\bar{3}

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0
3 years ago
Which expression has the same value as 4÷25 in fraction form
otez555 [7]

Answer:

4/25

Step-by-step explanation:

It is a fraction with 4 in the numerator and 25 in the denominator.

4

__

25

6 0
3 years ago
Help me plz. You have to evaluate the expression.
Ray Of Light [21]

Answer:

2+4 + 0+ 1 = $7

Step-by-step explanation:

3 0
3 years ago
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