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Answer:
(a) rate of change = 8
(b) Function: y = 8x
(c) Domain: 0 ≤ x ≤ 2
Range: 0 ≤ y ≤ 16
Explanation:
Looks like a inverse variation sequence.
Inverse Variation formula: y = k(x)
Take two points: (1, 8), (2, 16)
Find the value of k which is constant also considered as <u>rate of change</u>.
<u>Insert values</u>:
===========
Equation: y = 8x
Domain lies in the x axis, Range lies in the y axis.
Answer:
<u>Problem A</u>
5 * 5 * x * x * x

<u>Problem B</u>
8 * 8 * 8

<u>Problem C</u>
4 * 4 * 4 * x * x * x * x

This distance can be expressed as 3.84×
m.
What is distance with example?
- Distance is a scalar quantity.
- The distance of an object can be defined as the complete path travelled by an object.
Given the distance between the earth and the moon is 384000km
Representing in exponential notation,
=384000×1000m [∵1km=1000m]
=384×
m
=3.84×
m
Learn more about distance
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<u>The correct question is -</u>
The distance between the Earth and the moon is approximately 384000 km. this distance can be expressed as ____m.