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The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
Learn more on midpoint of a line here: brainly.com/question/5566419
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<h2>|-6| +3|4| + |-5| - 0(6) </h2><h2>6+ 3(4) + |-5| - 0(6) </h2><h2>3(4) = 12 </h2><h2>6+12+|-5| -0(6) </h2><h2>6 + 12 = 18 </h2><h2>18 + |-5| - 0(6) </h2><h2>18 + 5 - 0(6) </h2><h2>18 + 5 = 23 </h2><h2>23 - 0(6) </h2><h2>0(6) = 0 </h2><h2>23 - 0 = 23 </h2><h2>Answer: 23 (Option C) </h2><h2>Good luck on your assignment and enjoy your day! </h2><h2>~