Answer:
I think the correct answer for this is False.
Chromium and copper (ii) sulfate react according the reaction below;
2Cr + 3CuSO4 = 3Cu +Cr2(SO4)3
We can calculate the number of moles of CuSO4 present;
no of moles of CuSO4 = 0.75 × 0.125 = 0.09735 moles
According to the reaction the mole ratio is 2 : 3
Moles of Chromium = (0.09735 × 2)/3
= 0.0625 Moles
Mass of chromium = 0.0625 moles × 52 g/mole
= 3.25 g of chromium
Inversely -think of 1/2 and 2/1 as being inverse. So is 1/3 and 3/1
Answer:
T = -28.2 °C
Solution:
Data Given;
P = 1820 mmHg = 2.39 atm
V = 5.12 L
m = 19.4 g
R = 0.0821 atm.L.mol⁻¹.K⁻¹
Calculating moles,
n = 19.4 g ÷ 32 g.mol⁻¹
n = 0.606 mol
Assuming that the oxygen gas is acting perfectly, then according to Ideal Gas Equation,
P V = n R T
Solving for T,
T = P V / n R
Putting values,
T = (2.39 atm × 5.12 L) ÷ (0.606 mol × 0.0821 atm.L.mol⁻¹.K⁻¹)
T = 244.7 K
Or,
T = -28.2 °C
If you have two magnets with a S on one side and a N on the other, a balanced force would be the S on both magnets facing each other a unbalanced force would be an S side of one magnet and the N side of another magnet facing each other
