Answer:
<h2>put the bigger number on top then add </h2>
Explanation:
41.369
The answer is d I think. Don’t quote me if I’m wrong
For what exactly ? just for fun or for educational purposes?
First, we should get moles acetic acid = molarity * volume
=0.3 M * 0.5 L
= 0.15 mol
then, we should get moles acetate = molarity * volume
= 0.2 M * 0.5L
= 0.1 mol
then, we have to get moles of OH- which added:
moles OH- = molarity * volume
= 1 M * 0.02L
= 0.02 mol
when the reaction equation is:
CH3COOH + OH- → CH3COO- + H2O
moles acetic acid after adding OH- = (0.15-0.02)
= 0.13M
moles acetate after adding OH- = (0.1 + 0.02)
= 0.12 M
Total volume = 0.5 L + 0.02 L= 0.52 L
∴[acetic acid] = moles acetic acid after adding OH- / total volume
= 0.13mol / 0.52L
= 0.25 M
and [acetate ) = 0.12 mol / 0.52L
= 0.23 M
by using H-H equation we can get PH:
PH = Pka + ㏒[salt/acid]
when we have Ka = 1.8 x 10^-5
∴Pka = -㏒Ka
= -㏒ 1.8 x 10^-5
= 4.7
So by substitution:
∴ PH = 4.7 + ㏒[acetate/acetic acid]
= 4.7 + ㏒(0.23/0.25)
= 4.66
The kinetic energy that the liberated electron has in eV based on the given values is :
10.28 eV.
<h3>Explanation:</h3>
- 1 eV is the kinetic energy gained by an electron or proton when acted upon by a 1 volt potential difference. E = QV is the formula for energy in terms of charge and potential difference.
A photoelectron's maximum kinetic energy is given by
Emax = hf - W
- where h is Plank's constant,
- f is the incident photon's frequency, and
- W denotes the metal surface's work function.
here given,
f = 3.62 x 10¹⁵ Hz
W = 4.70 eV
by recalling the equation for a photoelectron's maximum kinetic energy with given values,
Emax = hf - W
= ((4.14 × 10⁻¹⁵eV.s)(3.62 x 10¹⁵ Hz)) - (4.70 eV)
= 10.28 eV
As a result, we discovered that the maximum kinetic energy of electrons is 10.28eV.
To learn more about kinetic energy of electrons refer to :
brainly.com/question/21208918
#SPJ13
