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3 years ago

Someone help me with this I will make you brain

Mathematics

1 answer:

vovangra [49]3 years ago

7 0

The third table would be your answer.

I know this because I turned both equations shown into graph form, this allowed me to see what the x-values of 1, 2, and 3 would have for y-values. My graph of both equations is shown in the picture below. (Green is f(x) = x + 4 and purple is g(x) = -2f(x))

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The temperature of a city changed by -24 degrees celsius over a 6-week period. The temperature changes by the same amount each w

Anton [14]

That amount, which I assume you're asking about, is a 4 degree drop in temperature each week.

3 0

3 years ago

Find the sum of 1st 18 terms of an AP whose nth term is 3-2n.

cricket20 [7]

Answer:

-288

Step-by-step explanation:

<h3>Given AP</h3>

t(n) = 3 - 2n

The sum of first 18 terms

<h3>Solution</h3>

Sn = 1/2n(t(1) + t(n))

<u>The first and 18th terms as per the formula</u>

t(1) = 3 - 2 = 1
t(18) = 3 - 18*2 = 3 - 36 = -33
S18 = 1/2*18(1 - 33) = 9*(-32) = -288

<u>Answer is</u> -288

3 0

3 years ago

Reduce the following fraction: -36x^4y^4z^5/-12x^6y^3z

Evgesh-ka [11]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{-36x^4y^4z^5}{-12x^6y^3z}\quad 
\begin{cases}
36=2\cdot 2\cdot 3\cdot 3\\
12=2\cdot 2\cdot 3
\end{cases}\implies \cfrac{-36}{-12}\cdot \cfrac{x^4y^4z^5}{x^6y^3z^1}
\\\\\\
\cfrac{\underline{-2\cdot 2\cdot 3}\cdot 3}{\underline{-2\cdot 2\cdot 3}}\cdot \cfrac{x^4y^4z^5x^{-6}y^{-3}z^{-1}}{1}\implies \cfrac{3}{1}\cdot 
\cfrac{x^4x^{-6}y^4y^{-3}z^5z^{-1}}{1}$

$\bf \cfrac{3}{1}\cdot \cfrac{x^{4-6}y^{4-3}z^{5-1}}{1}\implies 
\cfrac{3}{1}\cdot\cfrac{x^{-2}y^{1}z^4}{1}\implies 
\cfrac{3x^{-2}yz^4}{1}\implies \cfrac{3yz^4}{x^2}$

6 0

3 years ago

Is this proportional?<br> Questions answered: 60<br> Questions asked: 6

sineoko [7]

Brainly is a site used for help. There is no proportions for questions asked or answered. You may ask however many questions you want as long as they follow guidelines. We are all here to help you! :)

Even if the questions asked goes over the questions answered that is not a bad thing at all.

Hope this helped you. Have a great day!

4 0

4 years ago

Read 2 more answers

Not sure how to solve the following equations.

diamong [38]

Answer:

do the math

Step-by-step explanation:

6 0

3 years ago