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In-s [12.5K]
3 years ago
8

PLZZ Help me algebra 2.

Mathematics
1 answer:
Kipish [7]3 years ago
7 0

Answer:

32

Step-by-step explanation:

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Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
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For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

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5 0
4 years ago
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