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lakkis [162]
3 years ago
10

3) A school's enrollment in 2019 was 692 students. In 2020 they enrolled 852 students. What was the % increase in students from

2019 to 2020?
A. 18.8%
B. 69.2%
C. 85.2%
D. 23.1%
E. None of the above
Mathematics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

D. 23.1%

Step-by-step explanation:

852-692=160    160/692=0.231213873  rounds to 0.231  move decimal over two places to the right to make it percent which is 23.1%

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Convert 500erg into joule<br>​
Sever21 [200]

Answer:

500 erg = 500×10^-5

= 0.00500 J

Step-by-step explanation:

Please mark as brainliest

4 0
3 years ago
Given:f(x)=3x^2+1,G(x)=2x-3,H(x)=x<br> F(-2)=<br> a.13<br> b.37<br> c.-11
olga55 [171]

Answer:

13 is the answer:)

Step-by-step explanation:

f(-2)= 3* (-2)² + 1

= 3*4 + 1

= 13

7 0
2 years ago
Find (a) the range and (b) the standard deviation of the data set 40,35.45,55,60. Round to the nearest hundredth if necessary.
zmey [24]

Answer:

(a) 25

(b) 9.27

Step-by-step explanation:

Step 1

We have to rearrange the given days set from least to highest

35, 40, 45, 55, 60

(a) the range

Range = The highest number - The least number

= 60 - 35

= 25

(b) the standard deviation of the data set

35, 40, 45, 55, 60.

We find the Mean

Mean = Sum of values/Number of values

= 35+40+45+55+60/5

= 235/5

= 47

We can find the standard deviation now.

The formula =

√(x - Mean)²/n

= √(35 - 47)²+ (40 + 47)² + (45 - 47)² + (55 - 47)² + (60 - 47)²/5

= √144 + 49 + 4 + 64 +169/5

= √430/5

= √86

= 9.273618495

Approximately = 9.27

5 0
3 years ago
Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a
Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}

(a). Exactly one face up is red.

The odds of only the first die being red are:

P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}

The probability that all die turn up red is:

P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}

Thus, the probability that at least one die turns up red is:

P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}

4 0
3 years ago
Please answer this for me pleaseeeee
kobusy [5.1K]

Answer:

\Huge\boxed{x=71.9}

Step-by-step explanation:

Hello There!

Once again we are going to use trigonometry to solve for x

Here are the <u>Trigonometric Ratios</u>

sin = opposite divided by hypotenuse

cos = adjacent divided by hypotenuse

tan = opposite divided by adjacent

we need to find x and we are given its opposite side length (58) and the adjacent side length (19)

this corresponds with tangent so once again we will be using tangent to solve for x

Looking at tangent we see that its equal to opposite divided by adjacent so we create an equation

tan(x)=\frac{58}{19}\\\frac{58}{19} =3.052631579

now we have

tan(x)=3.052631579

Once again we need to get rid of the tan

to do so we take the inverse of tan ( tan^-1) and apply it to each side

arcsin^-^1(tan(x))=x\\arcsin^-^1(3.052631579)=71.86191784

finally we round to the nearest tenth

we're left with x = 71.9

4 0
3 years ago
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