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lakkis [162]
3 years ago
10

3) A school's enrollment in 2019 was 692 students. In 2020 they enrolled 852 students. What was the % increase in students from

2019 to 2020?
A. 18.8%
B. 69.2%
C. 85.2%
D. 23.1%
E. None of the above
Mathematics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

D. 23.1%

Step-by-step explanation:

852-692=160    160/692=0.231213873  rounds to 0.231  move decimal over two places to the right to make it percent which is 23.1%

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SAT Scores 1510 1480 2100 1800 1300 1250 1400 1430 1390 1520 The SAT scores for a group of 10 students are shown. What is the me
Minchanka [31]

Answer:

1580.0

Step-by-step explanation:

- Add all numbers and divide them by 10 (the amount of numbers).

- Mean is when you add all the numbers and divide them by how many their are.

3 0
3 years ago
How to figure out 168=-8x
S_A_V [24]
168=-8x
-8     -x
-21 = x

Division, 168 divided by -8
4 0
3 years ago
Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

3 0
3 years ago
A rectangle with sides measuring x in. and 4x-1 in. has an area of 663in.^2. What are the dimensions of the rectangle?
serious [3.7K]

9514 1404 393

Answer:

  13 in by 51 in

Step-by-step explanation:

The area is the product of the dimensions, so is ...

  663 = x(4x -1)

  4x^2 -x -663 = 0 . . . . . . subtract 663 to put in standard form

Using the quadratic formula, we can find the solutions.

  x = (-(-1) ±√((-1)^2 -4(4)(-663)))/(2(4))

  x = (1 ± √10609)/8 = (1 ±103)/8

Only the positive solution is of any use in this problem, so ...

  x = 104/8 = 13

  4x-1 = 4(13)-1 = 51

The dimensions of the rectangle are 13 inches by 51 inches.

__

I find it easiest to solve these using a graphing calculator.

8 0
3 years ago
80 as a product of prime factors
laila [671]
80
8 x 10
2 x 4 x 5 x 2
2 x 2 x 2 x 2 x 5 <===
4 0
2 years ago
Read 2 more answers
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