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yulyashka [42]
3 years ago
12

For what value of the variable: is the value of 2x+1 twenty greater than 8x+5?

Mathematics
2 answers:
Alenkasestr [34]3 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

We would like to find the value of x such that:

2x + 1 = (8x + 5) + 20

Here, notice that the "+ 20" part mathematically represents the "twenty greater" phrase in the problem.

Now, we simply solve for x:

2x + 1 = 8x + 5 + 20

2x + 1 = 8x + 25

6x = 24

x = 4

The answer is thus 4.

<em>~ an aesthetics lover</em>

zepelin [54]3 years ago
5 0

Answer:

x = -4.

Step-by-step explanation:

The question asks when is 2x + 1 20 more than 8x + 5, which is the same thing as when is 2x + 1 equal to 20 plus 8x plus 5.

2x + 1 = 8x + 5 + 20

2x - 8x = 25 - 1

-6x = 24

x = -4

Hope this helps!

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GIVING BRAINLIEST AND 20 points!
mestny [16]

Answer:

The answer is 27

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(3y+6+3)=196−16

(2)(3y)+(2)(6)+(2)(3)=196+−16(Distribute)

6y+12+6=196+−16

(6y)+(12+6)=(196+−16)(Combine Like Terms)

6y+18=180

6y+18=180

Step 2: Subtract 18 from both sides.

6y+18−18=180−18

6y=162

Step 3: Divide both sides by 6.

6y

/6

=

162

/6

y=27

3 0
2 years ago
Can 0.2 0.6 3 and 9 make 24?
saveliy_v [14]

Answer:

Yes

Step-by-step explanation:

9 x 3 - (0.6/0.2)   Simplify the parentheses

9 x 3 - 3               Multiply 9 by 3

27 - 3                   Subtract

24

5 0
3 years ago
Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin
Artemon [7]
"<span>Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find \bar{d}, s_{d}, the t-test statistic, and the critical values to test the claim that \mu_{d} = 0"

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find </span><span>\bar{d}
You are asked to find the mean difference between the two variables, which is given by the formula:
\bar{d} =  \frac{\sum (x - y)}{n}

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example: 
</span><span>\bar{d} =  \frac{6}{8} = 0.75</span>

B) Find <span>s_{d}
</span><span>You are asked to find the standard deviation, which is given by the formula:
</span>s_{d} =  \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }

These are the steps to follow:
1) Subtract the mean difference from each pair's difference 
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
s_{d} = \sqrt{ \frac{101.5}{8-1} }
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
t =  \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}

where SE = standard error is given by the formula:
SE =  \frac{ s_{d} }{ \sqrt{n} }

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract  \mu_{d}
6) divide by the standard error

In our example:
SE = 3.81 / √8
      = 1.346

The problem gives us <span>\mu_{d} = 0, therefore:
t = [(9.75 - 9) - 0] / 1.346</span>
  = 0.56

D) Find t_{\alpha / 2}
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find <span>t_{\alpha / 2} = 1.895</span>

Since our t-value is less than <span>t_{\alpha / 2}</span> we can reject our null hypothesis!!

7 0
3 years ago
If d = 390 mi, and r = 60 mi/h. what is the value of time (t)?
Jobisdone [24]
D = 390mi
r = 60 mi/h

390/60 = 6.5

(t) = 6.5 h
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3 years ago
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