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gizmo_the_mogwai [7]
2 years ago
8

What is the solution to the equation 2 ( 5 + 2 x ) = − 4 + 6 x ? x = 3 2 x = 3 2 x = 7 6 x = 7 6 x = 2 x = 2 x = 7 x = 7

Mathematics
1 answer:
soldi70 [24.7K]2 years ago
5 0

Answer:

7=x

Step-by-step explanation:

multiply 5 and 2x by 2, you'll then have (10+4x)=-4+6x. Then add 4 to both sides and you have (14+4x)=6x. Subtract 4x from both sides and that'll get you 14=2x and you divide 2 from each side to get x by itself so 7 is your answer.

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Given the following functions, find the indicated values.
allsm [11]

Answer:

A. f(-2)=3-6(-2)

-2f =3-(-12)

-2f=3+12

=15

divide both sides by 2

f=15/2

B. f(0)=3-6(0)

f=3

C.f(4)=3-6(4)

4f=3-24

f=21/4

5 0
3 years ago
Solve for x: V x + 6 = 7​
MrRissso [65]

Answer:

x > 0, if not 4/x < 0

0 < 4/x < 6/7

0 < 28/x < 6

0 < 28 < 6x

0 < 4 2/3 < x

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please do this I need help ASAP
Doss [256]

Answer:

y-5=3 can be the correct answer

3 0
3 years ago
What is the unit cost?
Katena32 [7]

Answer:

The unit cost is 6

Step-by-step explanation:

Notice how the first point lands on (2,12) and how a "unit cost" is per one unit. So, if you divide 12 by 2, you would get a unit cost of 6.

4 0
3 years ago
Help anyone plezzzzzzzzzzzzzzzzzzz
emmainna [20.7K]
              <span> Direct-substituting x = -2 gives 0/0, so we know that by the factor theorem, both the numerator and denominator have a factor of x + 2. From there, we can cancel out the conflicting factors and apply the limit.

We can factor the numerator and denominator to get:

x^3 - x^2 - x + 10 = (x + 2)(x^2 - 3x + 5)
x^2 + 3x + 2 = (x + 2)(x + 1).

So we have:

lim (x-->-2) (x^3 - x^2 - x + 10)/(x^2 + 3x + 2)
= lim (x-->-2) [(x + 2)(x^2 - 3x + 5)]/[(x + 2)(x + 1)]
= lim (x-->-2) (x^2 - 3x + 5)/(x + 1), by canceling out x + 2
= [2^2 - 3(-2) + 5]/(-2 + 1)
= (4 + 6 + 5)/(-1)
= -15.

I hope this helps! </span>
7 0
3 years ago
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