A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
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Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
AB = CB
Because they are congruent
Therefore CB = 5.9
Given perimeter = 17
CB+BE+ED+DC = 17
5.9 + BE + 2.8 + 5.6 = 17
BE + 14.3 = 17
BE = 17 - 14.3
= 2.7
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Answer:
The point (2, -1 ) is not on the graph of the line.
Step-by-step explanation:
3x–4y–12=0
3*2 - 4*(-1) - 12= 0
6 + 4 - 12 =0
10 - 12 = 0
- 2 = 0 , false, so the point (2, -1 ) is not on the graph of the line.
Answer:
D
If you put the equation into a calculator, it will show a graph of it.
-12x/-4= -27
(-4)-12x/-4 it will cancel the 4 but you gotta multiply on the other side by 4 too
now have -12x =108
-12x=108
divide 108 by -12x which x=-9
