The equation of a line that pasees through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so given
point is (8,2) and slope is 5/8
y-2=5/8(x-8)
if you wanted slope intercept form
y-2=5/8x-5
y=5/8x-3
if you wanted standard form
5/8x-y=3
5x-8y=24
Answer:
![(2x-1)^2](https://tex.z-dn.net/?f=%282x-1%29%5E2)
Step-by-step explanation:
![4x^2-4x+1=\\(2x)^2+2(2x)(-1)+(-1)^2\\\\\textrm{Using the rule }A^2+2AB+B^2=(A+B)^2\textrm{, then:}\\(2x)^2+2(2x)(-1)+(-1)^2=(2x-1)^2](https://tex.z-dn.net/?f=4x%5E2-4x%2B1%3D%5C%5C%282x%29%5E2%2B2%282x%29%28-1%29%2B%28-1%29%5E2%5C%5C%5C%5C%5Ctextrm%7BUsing%20the%20rule%20%7DA%5E2%2B2AB%2BB%5E2%3D%28A%2BB%29%5E2%5Ctextrm%7B%2C%20then%3A%7D%5C%5C%282x%29%5E2%2B2%282x%29%28-1%29%2B%28-1%29%5E2%3D%282x-1%29%5E2)
N = 25. I subtracted 87-37 = 50, 50/2 = 25. Hope that makes sense.