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ahrayia [7]
3 years ago
8

What is 4 3/4 + 7/8 showing all work

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
4 \frac{3}{4} + \frac{7}{8}

Convert  mixed numbers  to improper fractions

=  \frac{19}{4} + \frac{7}{8}

Find de LCD  for 4 and 8 :

Factor each denominator  into its primes:

4 = 2^2


8 = 2^3

Find the  least common denominator 2^3 = 8

Adjust  fractions  based on  the LCD :

\frac{19*2}{8} +  \frac{7}{8}

Since the  denominators are equal , combine the fractions:

\frac{2*19+7}{8}

\frac{38+7}{8}

=  \frac{45}{8}

Therefore:

Convert  improper fractions to mixed numbers

= 5 \frac{5}{8}

hope this helps!
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20-gallon gas tax can go 25 miles on 1 gallon if the tank is full at the beginning of a 725 miles trip how many times does the d
Sergio039 [100]
725/25 = 29

The driver will have to refill the gas tank 29 times during the 725 miles trip.


I hope this helped you! c:
6 0
3 years ago
The circumference of a circle is 78π cm. Find the diameter, the radius, and the length of an arc of 140°.
jasenka [17]
 The correct answer is the option D, which is: <span>D. 78 cm; 39 cm; 30.3π cm
 The explanation is shown above:
 1-The formula for calculate the circumference of a circle is:
 C=2</span>πr
 78π=2πr
 2- The radius is:
 r=78π/2π
 r=39 cm
 3- The diameter is:
 D=39 cm x 2
 D=78 cm
 4- The arc length is:
 arc length=(140°π/180°)(39 cm)
 arc length=30.3π cm
 
5 0
4 years ago
If the area of a circle below is 18ft, what is the area of the shaded sector?
erik [133]
The Shaded area is .25 of the circle, so:

Area/4 = Shaded

18/4 = Shaded

4.5 = Shaded

Hope this helps!
8 0
4 years ago
What is the volume of a cylinder, in cubic inches, with a height of 2 inches and a base diameter of 18 inches? Round to the near
QveST [7]

Answer:

V≈508.94in³

Step-by-step explanation:

V≈508.94in³ nearest 10th will be 510 in3

8 0
3 years ago
Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your
Keith_Richards [23]

Answer:

Step-by-step explanation:

f'(x)=-sin x

f'(x)=\frac{cos \frac{\pi }{3} -cos (\frac{-\pi }{3}) }{\frac{\pi }{3} -(\frac{-\pi }{3}) } \\-sin x=\frac{\frac{1}{2} -\frac{1}{2} }{\frac{\pi }{3} +\frac{\pi }{3} } \\sin x=0\\at x=c ,sin c=0,c=0

c=0∈(-π/3,π/3)

4 0
3 years ago
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