So you want two groups that are in a ratio of 4 to 7
so 33=4x+7x
so 33=11x
so x=3
that means the groups are 4*3= 12 and 7*3=21
1 gal 2 qts 3 pts
1 gal 3 qts 7 pts
1 gal 3 qts 3 pts
---------------------------add
3 gal 8 qts 13 pts
1 pt = 0.5 qts...so 12 pts = 12* 0.5 = 6...so now we have :
3 gal 14 qts 1 pt
1 qt = 0.25 gal..so 12 qts = 12 * 0.25 = 3 gallons...so now we have :
6 gal 2 qts 1 pt <===
Answer: OPTION B.
Step-by-step explanation:
Given the following System of equations:
You can use the Elimination Method to solve it. The steps are:
1. You can mutliply the second equation by -3.
2. Then you must add the equations.
3. Solve for the variable "y".
Then:
4. Now that you know the value of the variable "y", you must substitute it into any original equation.
5. The final step is to solve for "x" in order to find its value.
Then:
Therefore, the solution is:
Answer:
6 .Cant find the answer there
cos i had 3b( 9c +3a +c )
7. -3x -17y
Do what that person with the long explanation says it’s most likely right!!