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1 year ago

13

Sanjay and his paving crew laid 40 yards of new pavement. Jack and his crew just took over, and they can lay 15 yards of new pav

ement per hour. If Jack's crew works an 8-hour shift, how much pavement will have been laid in all?

1 answer:

Mila [183]1 year ago

5 0

Answer:

$40 yds \: + 8hrs\times \frac{15yds}{hr } = \\ 40yds+ 120yds \: = 160yds$

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If p, q are zeroes of polynomial f(x) =2x^2-7x+3,find the value of p^2+q^2

Elza [17]

Answer:

p^2 + q^2 = 22/9.

Step-by-step explanation:

For a quadratic function ax^2 + bx + c if the zeroes are A and B then

A + B = -b/a and AB = c/a.

2x^2 - 7x + 3

Now p and q are the zeroes of the above function so

p + q = 7/3 and pq = 3/2.

Now p^2 + q^2 = (p + q)^2 - 2pq

= (7/3)^2 - 2* 3/2

= 49/9 - 3

= 49/4 - 27/9

= 22/9.

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2 years ago

Burger King sells burgers for $3.50 per burger. On Fridays, you can buy 2 burgers and get 1 free. They sold 500 burgers in 1 wee

faust18 [17]

Answer:

More information is needed, maximum weekly profit is $1750.

Step-by-step explanation:

The maximum profit would assume Burger King does not sell any burgers on Friday, therefore all 500 burgers were sold at $3.50. 500*$3.50 = $1750 in maximum earnings for the week. More information is needed about the split between the burgers sold over the week.

Maybe the question was trying to say 500 burgers were sold on Friday. In that case, assuming every customer got three burgers, 500/3 = 166.6 customers, rounding down because you cannot have half a customer, 166 customers on Friday. Each customer paid for two burgers 166*2*$3.50 = $1162 in earnings on Friday.

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2 years ago

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romanna [79]

Look AT IMAGE

Step-by-step explanation:

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2 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

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Answer:

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