Answer:
382000
Step-by-step explanation:
30
It’s a word problem for LCM
3 x 10 which will give you the lowest common multiple (LCM) also giving you the lowest number of clusters
Answer:
The correct option is;
26.8
Step-by-step explanation:
The given parameters are;
The perpendicular bisectors of the sides of ΔMNP = Segments OQ, OR, and OS
Therefore;
in Segment MN, segment QM = segment QN, by definition of bisected line
Segment OQ = Segment OQ by reflexive property
∠OQM = ∠OQN = 90° by definition of perpendicular bisector
∴ ΔOQN ≅ ΔOQM, by SAS rule of congruency
Segment MO ≅ Segment ON by Congruent Parts of Congruent Triangle are Congruent, CPCTC
Segment MO = Segment ON = 26.8, by definition of congruency
Segment MO = 26.8
Answer:
The least common multiple is 2y^2 - 50.
Step-by-step explanation:
Least common multiple means the lowest thing you can multiply them both to. For example, the LCM of 2 and 4 is 2, because 2*2 = 4 and 4*1 = 4.
First, factor 2y^2 - 50.
2 (y^2 - 25)
2 (y - 5)(y + 5)
Looks like if we wanted to get 2y^2 - 50 starting with y - 5, we'd have to multiply it by 2(y + 5).
2y^2 - 50 * 1 = 2y^2 - 50
y - 5 * 2(y + 5) = 2y^2 - 50
<u>So their least common multiple is 2y^2 - 50.</u>
