1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gre4nikov [31]
3 years ago
5

Suppose that the times it takes adult women to run a mile are normally distributed with an unknown mean and standard deviation.

The mile times of 29 randomly sampled adult women are used to estimate the mean of the population. Use Excel to calculate the t-score that should be used to find the 95% confidence interval for the population mean.
Round your answer to three decimal places.
Mathematics
1 answer:
Inga [223]3 years ago
8 0

Answer:

Step-by-step explanation:

You might be interested in
PLEASE HELP ASAP!!!!! LOTS OF POINTS
Hoochie [10]
D. It is not linear
6 0
3 years ago
Read 2 more answers
Linear or non linear​
nevsk [136]

Answer:

Linear.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What is the degree and leading coefficient?<br><br> -y-18y^6+8+3y^5
Lina20 [59]
Degree is 6 and the leading coefficient is -18
4 0
3 years ago
Write and solve an problem that illustrates the use of the find a pattern strategy. ​
lutik1710 [3]

Answer:

I don't know either

Step-by-step explanation:

8 0
3 years ago
1. Find the quartiles for the tire pressures of car tires at an auto clinic. Tire pressure is measured in psi
marusya05 [52]

The quartiles and outliers for the data provided are as follows:

1. Quartiles for the tire pressures of car tires at an auto clinic:

  • Q2 = 28 psi
  • Q4 = 36 psi
  • Q1 = 21.5 psi
  • Q3 = 34 psi

2. The outlier(s) for the tires prices is $450

3. The outlier(s) for the tires prices is $650

4. The outlier(s) for the tires prices is $540

5. Quartiles for the tire pressures of car tires at an auto clinic are:

  • Q2 = 27 psi
  • Q4 = 35 psi
  • Q1 = 23.5 psi
  • Q3 = 33 psi

<h3>Quartiles</h3>

  • Quartiles are the values that divide a list of numbers into four parts or quarters after the numbers are arranged in ascending order.

They describe the dispersionof a set of data values.

  • Q1 is the first quartile or lower quartile. 25% of the numbers in the data set are at or below Q1.
  • Q2 is the second quartile. 50% of the numbers are below Q2, and
  • Q3 is the third quartile, or upper quartile. 75% of the numbers are at or below Q3.
  • Q4 is the maximum value in the data set. 100% of the numbers are at or below Q4.

<h3>Outliers</h3>

Outliers are data points that differs significantly from other observations.

There are two outliers: lower boundary outliers and upper boundary outliers.

  • Formula for lower boundary outliers is:

Q1 − 1.5(IQR)

  • Formula for upper boundary outliers is:

Q3 + 1.5(IQR)

where IQR is interquartile range

  • IQR = Q3 - Q1

<h3>1. Quartiles for the tire pressures of car tires at an auto clinic: (20, 27,19, 23, 29, 28, 34, 34, 36)</h3>

Arranging in increasing order:

19, 20, 23, 27, 28, 29, 34, 34, 36.

Q2 = 28

Q4 = 36

Q1 = (20 + 23) / 2

Q1 = 21.5

Q3 = (34 + 34) /2

Q3 = 34

<h3>2. Outlier(s) for these tires prices: $58, $95, $78, $125, $87, $158, $152, $182, $195, $450</h3>

Arranging in increasing order:

58, 78, 87, 95, 125, 152, 158, 182, 195, 450

Q1 = (87 + 78)/2

Q1 = 62.5

Q3 = 182 + 195/2

Q3 = 188.5

IQR = 188.5 - 62.5

IQR = 126

Lower boundary outlier(s) = 62.5 - 1.5(126)

Lower boundary outliers = -126.5

Thus there are no lower outliers.

Upper boundary outliers = 188.5 + 1.5(126)

Upper boundary outliers = 377.5

Therefore, 450 is an outlier.

<h3>3. The outlier(s) for these tires prices: $78, $195, $98, $145, $87, $138, $159, $172, $155, $210, $240, $650</h3>

Arranging in increasing order:

78, 87, 98, 138, 145, 155, 159, 172, 195, 210, 240, 650

Q1 = 98

Q3 = 210

IQR = 210 - 98

IQR = 112

Lower boundary outlier(s) = 98 - 1.5(168)

Lower boundary outliers = -70

Thus there are no lower outliers.

Upper boundary outliers = 210 + 1.5(112)

Upper boundary outliers = 378

Therefore, 650 is an outlier.

<h3>4. The outlier(s) for these tires prices: $88, $135, $75, $135, $85, $168, $156, $192, $195, $210, $230, $245, $540</h3>

Arranging in increasing order:

75, 85, 88, 135, 135, 156, 168, 192, 195, 210, 230, 245, 540

Q1 = (88 + 135)/2

Q1 = 111.5

Q3 = (210 + 230)/2

Q3 = 220

IQR = 220 - 111.5

IQR = 108.5

Lower boundary outlier(s) = 111.5 - 1.5(108.5)

Lower boundary outliers = - 51.25

Thus, there are no lower outliers.

Upper boundary outliers = 220 + 1.5(111.5)

Upper boundary outliers = 387.25

Therefore, 540 is an outlier.

<h3>5. Quartiles for the tire pressures of car tires at an auto clinic: 23, 29,18, 24, 27, 24, 35, 32, 34</h3>

Arranging in increasing order:

18, 23, 24, 24, 27, 29, 32, 34, 35.

Q2 = 27

Q4 = 35

Q1 = (23 + 24) / 2

Q1 = 23.5

Q3 = (32 + 34) /2

Q3 = 33

Learn more about quartiles and outliers at: brainly.com/question/24805469

4 0
3 years ago
Other questions:
  • Which graph best represents the function f(x) = 1(1.5)x?
    5·1 answer
  • PLEASE HELP GEOMETRY!!!
    14·1 answer
  • The distance from Kenya's house to her job is 18 miles. One morning she left her house at 7:15 a.m. She traveled at the rate of
    6·1 answer
  • Christian reads 14 book every 23 week.
    15·1 answer
  • C+d is the of c and d
    8·1 answer
  • Jackie wants to create a scale drawing of the poster shown below: A rectangle is shown. The length of the rectangle is labeled 4
    15·1 answer
  • The perimeter of a rectangle is 90 inches. The width of the rectangle is 9 inches less than the length of the rectangle find the
    6·1 answer
  • An interest-free period during which a credit card owner can pay off a balance
    14·1 answer
  • Consider the sequence 3, 9, 15, 21, ...
    8·1 answer
  • The graph shows the favorite activities of campers at a summer camp. Suppose there are 300 campers at the camp. How many campers
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!