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Romashka-Z-Leto [24]
3 years ago
8

C+d is the of c and d

Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

sum

Step-by-step explanation:

The sum of c and d is c+d.

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Calculate the unpaid balance, finance charge, and new balance using the unpaid balance method. Note: interest rate is given as a
quester [9]

Previous balance = $291.96

Payments/credits = $45.00

Unpaid balance = $ 291.96 - $45.00 = $ 246.96

Monthly Interest rate = 1.5 %

Finance charge = 1.5 % of $ 246.96= $3.70

Total balance to be paid when Finance charge is included = $ 246.96 + $3.70= $ 250.66

New purchases = $103.98

New balance =  $ 250.66 + $103.98 = $ 354.64


8 0
3 years ago
Your apartment is at (0, 0) on a coordinate plane. You want to go to Chicken Shack (CS) and get some tasty chicken tenders, with
Ainat [17]

Answer:

The answer is below

Step-by-step explanation:

The distance between two points on a coordinate plane is given by:

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given the location of the apartment (AP) is at A(0,0), the Chicken Shack's (CS) location is at C(3, 4) and Baskin Robbins (BR) is at the location B(- 4, 4). Hence the following distance are:

|AB|=\sqrt{(-4-0)^2+(4-0)^2} =4\sqrt{2}\ units\\\\|AC|=\sqrt{(3-0)^2+(4-0)^2}=5\ units  \\\\|BC|=\sqrt{(3-(-4))^2+(4-4)^2}=7\ units

Hence the total distance travelled = distance between the apartment and chicken shack +distance between apartment and Baskin Robbins + distance between Baskin Robbins and chicken shack

total distance travelled = AB + BC + AC = 4√2 + 7 + 5

total distance travelled = 17.66 units

4 0
3 years ago
Express x-1y-2/z-3 with positive exponents.
Marysya12 [62]

x^-1y^-2/z^-3

=z^3 / (xy^2)

8 0
3 years ago
Read 2 more answers
An educational organization in California is interested in estimating the mean number of minutes per day that children between t
Hatshy [7]

Answer:

The critical value for a 98% CI is z=2.33.

The 98% confidence interval for the mean is (187.76, 194.84).

Step-by-step explanation:

We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.

We know the standard deveiation of the population (σ=21.5 min.).

The sample mean is 191.3 minutes, with a sample size n=200.

The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.

The margin of error is:

E=z\cdot \sigma/\sqrt{n}=2.33*21.5/\sqrt{200}=50.095/14.142=3.54

With this margin of error, we can calculate the lower and upper bounds of the CI:

LL=\bar x-z\cdot\sigma/\sqrt{n}=191.3-3.54=187.76\\\\\\UL=\bar x+z\cdot\sigma/\sqrt{n}=191.3+3.54=194.84

The 98% confidence interval for the mean is (187.76, 194.84).

4 0
3 years ago
The ratio of teachers to students at Pikeville College is 1: 20. If there are 3,000 students at the college,
galben [10]
There are 150 teachers because 20 * 150 is 3000.
7 0
3 years ago
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