Option A
The restaurant Manager can afford at most 10 employees for the day
<em><u>Solution:</u></em>
Given that restaurant manager can spend at most $600 a day for operating costs and payroll
It costs $100 each day to operate the bank and $50 dollars a day for each employee
The given inequality is:

Where , "x" is the number of employees per day
Let us solve the inequality for "x"

Add -100 on both sides of inequality

Divide by 50 on both sides of inequality

Hence the restaurant Manager can afford at most 10 employees for the day
Thus option A is correct
Answer:
14, 16, 18
Step-by-step explanation:
x + (x+2) + (x+4)= 48
3x + 6 = 48
3x = 42
x = 14
x+2 = 16
x+4 = 18
Answer:
Step-by-step explanation:
Use the Law of Cosines
A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°
Answer:
(a)
(b)
(c)43 times
Step-by-step explanation:
<u>Part A</u>
The paper's thickness = 0.05mm
When the paper is folded, its width doubles (increases by 100%).
The thickness of the paper grows exponentially and can be modeled by the function:

<u>Part B</u>
<u />
<u />
<u />
<u>Part C</u>
If the thickness of the paper, g(n)=384,472,300,000 mm
Then:

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.
sqrt(81) = 9
sqrt(100) = 100
sqrt(92) is between 9 and 10.
Answer: 10