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2 years ago

Figure ABCD is transformed to A′B′C′D′, as shown:

Mathematics

1 answer:

Mrrafil [7]2 years ago

3 0

Answer:

Picture please. and answer.

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The perimeter of a rhombus is 560 meters and one of its diagonals has a length of 76 meters. Find the area of the rhombus.

borishaifa [10]

The perimeter is the sum of the side lengths of a shape. <span> A </span>diagonal is a line segment joining two vertices of a polygon or polyhedron <span>when those vertices are not on the same edge. We calculate as follows:

Perimeter = 4a
560 = 4a
a = 140 meters

</span>A=(1/2)d√(4a^2 - d^2)
A = 10240.56 m^2

4 0

2 years ago

The altitude drawn to the hypotenuse of a right triangle divides the hypotenuse into segments of lengths 4 and 12. Find the leng

Ostrovityanka [42]

Answer:

8 units.

Step-by-step explanation:

The smaller of the right triangles formed is similar to the whole triangle so

4/x = x/16 where x = the shorter leg

x^2 = 64

x = 8.

7 0

2 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0

2 years ago

Find the volume of this sphere 30 POINTS

Vitek1552 [10]

Answer:

V≈33.51

Step-by-step explanation:

Solve for volume

V=4/3πr3

=43·π·23≈33.51032

7 0

2 years ago

Find the distance between the points L(7,-1) and M(-2, 4).

zysi [14]

Answer:

The answer is

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

L(7,-1) and M(-2, 4)

The distance between them is

$|LM| = \sqrt{ ({7 + 2})^{2} + ( { - 1 - 4})^{2} } \\ = \sqrt{ {9}^{2} + ({ - 5})^{2} } \\ = \sqrt{81 + 25} \\ = \sqrt{106} \: \: \: \: \: \: \: \\ = 10.29563014...$

We have the final answer as

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Hope this helps you

4 0

2 years ago