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SSSSS [86.1K]
2 years ago
13

What is the slope of the line on the graph? Enter your answer in the box.

Mathematics
2 answers:
Andrews [41]2 years ago
7 0

Answer:

slope = -1/3

Step-by-step explanation:

Drupady [299]2 years ago
6 0
It’s rise over run so 1 down 3 to right and it’s a decreasing slope so -1/3 is the slope
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(2x - 3y + 1) + (4x + y + 5)=​
disa [49]
6x-2y+5. Here you just do addition/subtraction with the coefficients on the variables.
3 0
3 years ago
The Organic Cafe recently served 9 cinnamon rolls and 9 other pastries. Considering this data, how many of the next 14 pastries
VladimirAG [237]

Answer

idk maybe 5 is the flvs?

Step-by-step explanation:

8 0
3 years ago
Solve for g.<br> 3 =g/-4-5
Leviafan [203]
<h2>g = -27</h2>

Step-by-step explanation:

3 =  \frac{g}{ - 4 - 5}

Simplify

- 4 - 5 =  - 9 \\  \\ 3 =  \frac{g}{ - 9}

Cross Multiply

3 \times  - 9 = g \\  - 27 = g \\ g =  - 27

6 0
3 years ago
Read 2 more answers
The radius of the base of a cylinder is 10 centimeters and its height is 20 centimeters A cone is used to fill the cylinder with
rewona [7]

Answer:

24 times

Step-by-step explanation:

cone is used to fill cylinder

conevolume times x=cylindervolume

so

x=cylinderv/conev

cylinderv=hpir^2

conevolume=1/3hpir^2

cylinder:

v=hpir^2

r=10

h=20

v=20*pi*10^2=2000π

cone=1/3hπr²

r=5

h=10

v=1/3(10)π5²=250π/3

volume of cylinder ÷ volume of cone

= 2000π ÷ (250π÷3)

= 6000π ÷ 250π

= 600÷25

= 24

please mark me brainliest

6 0
3 years ago
a river flows due south at 1.2 miles per hour. A swimmer attempting to cross the river heads due east swiming at 3 miles per hou
kotegsom [21]

Answer:

The swimmer must move in the direction 338.2°

Step-by-step explanation:

Since the river flows due south at 1.2 miles per hour and the swimmer swims 3 miles per hour due east of the river, since their directions are perpendicular,  the resultant speed is the hypotenuse of the triangle formed by the two perpendicular directions.

The direction of the resultant speed is thus θ = tan⁻¹( vertical component/horizontal component) where vertical component = 1.2 mph due south = -1.2 mph and horizontal component = 3 mph due east = + 3 mph

So, θ = tan⁻¹(-1.2 mph/+ 3mph)

θ = tan⁻¹(-1.2/3)

θ = tan⁻¹(-0.4)

θ = -21.8°

θ = -21.8° + 360° (since we are in the fourth quadrant- between east and south)

θ = 338.2°

So, <u>the swimmer must move in the direction 338.2°</u>.

4 0
2 years ago
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