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3 years ago

Ill give brainliest

2 answers:

8 0

All you have to do is plug in the input value in the place of x and then solve for y.

y = 2 (4.5) + 0.5
y = 9 + 0.5
y = 9.5

So the output value for the input of 4.5 is 9.5

Luba_88 [7]3 years ago

3 0

The answer is c. Because 4.5 * 2 is 9 then you add 0.5 so the answer is 9.5

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At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 6 cubic feet per minute. The dia

Alla [95]

Answer:

$0.2122\text{ ft per min}$

Step-by-step explanation:

Let r be the radius ( in feet ) of the cone,

So, the diameter of the cone = 2 × radius = 2r feet,

∵ The diameter of the base of the cone is three times the height,

If h represents the height of the cone,

⇒ 2r = 3 × h,

⇒ $r=\frac{3h}{2}$ feet,

∵ Volume of a cone,

$V=\frac{1}{3}\pi R^2 H$

Where,

R = radius, H = height,

Thus, the volume of the given cone is,

$V=\frac{1}{3}\pi r^2 h$

$=\frac{1}{3}\pi (\frac{3h}{2})^2 h$

$=\frac{3}{4}\pi h^3$

Differentiating with respect to t ( time )

$\frac{dV}{dt}=\frac{9}{4}\pi h^2\frac{dh}{dt}$

We have,

$\frac{dV}{dt}=6\text{ cubic ft per min},h=2\text{ feet}$

$6=\frac{9}{4}\pi (2)^2 \frac{dh}{dt}$

$6=9\pi \frac{dh}{dt}$

$\implies \frac{dh}{dt}=\frac{6}{9\pi }\approx 0.2122\text{ ft per min}$

4 0

3 years ago

You need to buy fertilizer for a circular flower bed with a diameter of 13 feet. If one bag will fertilize 10 square feet, how m

vfiekz [6]

The area of the circular flower bed
=(13÷2)^(2 × pie
≈132.73 sq.feet

the amount of fertilizer needed
132.73÷10
=13.273

Thus 14 bags of fertilizer will be needed

hope it helps

3 0

3 years ago

Write the period that has the number 913

Gala2k [10]

The answer is in the thousands group. Its the way they word the problem that complicates it. 913,256 256 being the ones group 913 being the thousands group. So the name of the period with 913, is the thousands group

4 0

3 years ago

Read 2 more answers

Suppose that you have a data set containing 1000 tests scores. How many scores would you expect to find matching each descriptio

NemiM [27]

70% because that is average grade

6 0

3 years ago

Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe

kramer

A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like $\sqrt{2}$ , you will end with a rational number: $( \sqrt{2} )^{2}=2$ , but, if you square rationals from different roots than square root like $\sqrt[3]{2}$ , you will end with an irrational number: $\sqrt[3]{2^{2} } = \sqrt[3]{2}$ .

D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

E.) square root of a is never rational
This one is false. The square root of perfect squares are always rational numbers: $\sqrt{64} =8$ , $\sqrt{16} =4$ ,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that a is a rational number and b be an irrational number, A, C, D, and F are true statements.

4 0

2 years ago