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2 years ago

Divide 36087 by 56 and verify the result by division algorithm.

Mathematics

1 answer:

patriot [66]2 years ago

5 0

Answer:

Do like this

Step-by-step explanation:

Hope it helps you

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The area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?

e-lub [12.9K]

Answer:

26.8cm²

Step-by-step explanation:

the area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?

Area of rectangle = length x width

53.6 = 4L x 1/2 W

53.6 = 2L × W

Divide both sides by 2

L × W = 53.6 ÷ 2

New area = 26.8cm²

I hope this was helpful, please mark as brainliest

5 0

3 years ago

(3x-3)° [6{x-10)]° what is the value of x

DerKrebs [107]

Solve for x over the real numbers:18 ° (x - 1) (x - 10 ° x) = 0
Divide both sides by 18 °:(x - 1) (x - 10 ° x) = 0
Split into two equations:x - 1 = 0 or x - 10 ° x = 0
Add 1 to both sides:x = 1 or x - 10 ° x = 0
Collect in terms of x:x = 1 or (1 - 10 °) x = 0
Divide both sides by 1 - 10 °:Answer: x = 1 or x = 0

4 0

3 years ago

Read 2 more answers

Please help! Please explain how to do this, I am so lost.

alexdok [17]

Ok, so we know that RST is equal to 6x+12
And RST is also equal to 78 + 3x-12
so we set them equal to each other

6x + 12 = 3x - 12 + 78
And simplify
3x = 54
x = 18

Finally, we solve for the angle with 18 for x

6(18) + 12
108 + 12
120

Hope this helps

8 0

2 years ago

NEED ANSWERS ASAP, 100 POINTS! There are twenty classes at each of two middle schools. The number of students in each class at e

DiKsa [7]

Note: You missed to add the dot plots chart. As I found the chart after a little research. Thus, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.

Answer:

'There are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

Step-by-step explanation:

From the diagram, it is clear that

The data set containing Poplar Middle School:

20 20 20 21 21 21 21 21 22 22 22 22 22 22 22 23 23 23 23 24

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

$\mu = 435/20$

$=\frac{87}{4}$

$= 21.75$

The data set containing Oak Middle School:

20 21 21 22 22 23 23 23 23 24 24 24 25 25 26 26 27 27 28 29

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

$\mu = 483/20$

$=24.15$

So, the difference in mean will be:

$24.15 - 21.75 = 2.4$

Therefore, 'there are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

5 0

2 years ago

Solve for (f+g)(5) if f(x)=6x+3 and g(x)=x-4 show you work please

Diano4ka-milaya [45]

There are two ways to do this.

The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34

OR

you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34

Either way, the final answer is 34

7 0

3 years ago

Divide 36087 by 56 and verify the result by division algorithm.​

Divide 36087 by 56 and verify the result by division algorithm.