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OLEGan [10]
3 years ago
10

Need answers 1-8 equations and problems solving

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

1) a. x = number of cars

b. x - 12

2) a. x = number of packages

b. 16 + 1/2x

3) a. x = number of coins

b. 1/2x - 6

4) 17 + x = 78

Subtract 17 from each side.

x = 61

5) x - 33 = 78

Add 33 to each side.

x = 111

6) x * 84 = 327.6

Divide each side by 84

x = 3.9

7) 1333/8.6 = 155

The speed was 155mph.

8) 2475/110 = 22.5

The trip took 22 and a half hours. (Or "The trip took 22.5 hours."

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Anybody know how to work on decay rate? I'll give brainliest. THIS IS DUE SOON SO PLEASE HELP
artcher [175]

Answer:

28%

Step-by-step explanation:

In the function the .72 means that each unit of time 72% of the value is retained. This means that 28% percent of the value is lost or decays because 1-0.72=0.28 or 28 percent.

3 0
3 years ago
A given line has the equation 2x + 12y = −1. What is the equation, in slope-intercept form, of the line that is perpendicular to
VikaD [51]

Answer:

y = 6x + 9

Step-by-step explanation:

The equation of a line in slope- interceot form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + 12y = - 1 into this form

Subtract 2x from both sides

12y = - 2x - 1 ( divide all terms by 12 )

y = - \frac{1}{6} x - \frac{1}{12} ← in slope- intercept form

with slope m = - \frac{1}{6}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{1}{6} } = 6

Note the line passes through (0, 9) on the y- axis ⇒ c = 9

y = 6x + 9 ← equation of perpendicular line

3 0
3 years ago
Read 2 more answers
1/2 minus 2/3 minus 3/4 divided by 1/4
amm1812
<span>I believe that the answer would be -0.35416666666</span>
7 0
3 years ago
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

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