Answer:
(6, 5)
Step-by-step explanation:
-3 + 9 = 6
15 - 10 = 5
We have two sides and one angle opposite to one of the known sides.
Begin with applying the Law of Sines to find angle A:

= <span>

Then, solve for sin A:
</span>sin A =

Now, plug in numbers:
sin A = 19 × sin(38) / 10 = 1.17
We know that it does not exist an angle whose sin is bigger than 1, therefore
no triangle is formed.
Answer: C . 147π / 4 mi²
Concept:
The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.
A = (θ / 360) πr²
θ = angle of the sector
π = constant
r = radius
Solve:
<u>Given variable</u>
θ = 270°
r = 7 mi
<u>Given formula</u>
A = (θ / 360) πr²
<u>Substitute values into the formula</u>
A = (270 / 360) π (7)²
<u>Simplify exponents</u>
A = (270 / 360) π 49
<u>Simplify by multiplication</u>
A = (147 / 4) π
A = 147π / 4
Hope this helps!! :)
Please let me know if you have any questions
Answer:
D. The intersection of the angle bisectors.
Step-by-step explanation:
The incenter is equidistant from each of the sides of the triangle. An angle bisector is the set of points equidistant from the sides, so the incenter is the place where the angle bisectors meet.
The quadratic formula is above.
You want each equation in standard form: ax^2 + bx + c = 0
I begin each problem by defining variables.
For instance 3. Is in standard form. X^2 -2x - 3 = 0. a = 1, b = -2, c = -3
Now use quadratic formula: x = [- b + or - sqrt(b^2 - 4ac)]\2a