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3 years ago

Need answers 1-8 equations and problems solving

Mathematics

1 answer:

djyliett [7]3 years ago

3 0

1) a. x = number of cars

b. x - 12

2) a. x = number of packages

b. 16 + 1/2x

3) a. x = number of coins

b. 1/2x - 6

4) 17 + x = 78

Subtract 17 from each side.

x = 61

5) x - 33 = 78

Add 33 to each side.

x = 111

6) x * 84 = 327.6

Divide each side by 84

x = 3.9

7) 1333/8.6 = 155

The speed was 155mph.

8) 2475/110 = 22.5

The trip took 22 and a half hours. (Or "The trip took 22.5 hours."

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Me Sidney rented a car for a day. The rental fee consists of flat rate of $19.99 plus 0.21 for an additional mile. For how how m

ipn [44]

19.99+0.21x=52.54

0.21x=32.55

x=155

Mr. Sidney drove 155 miles

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3 years ago

A young oak tree is planted when it is 5 cm tall. It grows 3 cm every month. Write an equation to describe its growth

Naily [24]

Answer:

y=3x+5

Since it's already 5 cm we have +5

every month it would go up by 3 cm so we have 3 and x is to represent the # of months.

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3 years ago

How would you write 8^5 as a multiplication expression? A. 8 × 5 B. 8 × 8 × 8 × 8 × 8 C. 5 × 5 × 5 × 5 × 5 × 5 × 5 × 5

Neporo4naja [7]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

if we ever face a number written in the form of $\underline{x^{n}}$ where x denotes the base and n denotes the exponent or power , we can expand it in the following way -

$x^{n} = x \times x \times x \times.... x ( upto\: " n " \: times )$

therefore ,

$8 {}^{5} = 8 \times 8 \times 8 \times 8 \times 8$

option ( B )

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4 0

2 years ago

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PLZ HELP, WILL GIVE BRAINLIEST!!!

ahrayia [7]

Answer:

i would say a senior citizen ticket i 3 dollars and the child tickets are 5 dollars

Step-by-step explanation:

7 0

3 years ago

The profit per acre from a grove of orange trees is given by x(190 − x) dollars, where x is the number of orange trees per acre.

nasty-shy [4]

Answer:

$P(x) = 190 x -x^2$

In order to maximize the last equation we can derivate the function in term of x and we got:

$\frac{dP}{dx} = 190 -2x$

And setting this derivate equal to 0 we got:

$\frac{dP}{dx} = 190 -2x=0$

And solving for x we got:

$x = 95$

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

$P(x=95)= 95(190-95)= 95*95 = 9025$

Step-by-step explanation:

For this case we have the following function for the profit:

$P(x) = x(190-x)$

And we can rewrite this expression like this:

$P(x) = 190 x -x^2$

In order to maximize the last equation we can derivate the function in term of x and we got:

$\frac{dP}{dx} = 190 -2x$

And setting this derivate equal to 0 we got:

$\frac{dP}{dx} = 190 -2x=0$

And solving for x we got:

$x = 95$

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

$P(x=95)= 95(190-95)= 95*95 = 9025$

7 0

3 years ago

Read 2 more answers