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olya-2409 [2.1K]
3 years ago
10

Need help in number 10!! Pleaseeeeeee

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0
L=3W
Area=LW=6627
Plug in the first one in the second one.
3WW=6627
W^2=2209
W=47
L=3*47=141
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Out of 132 seventh graders 33 voted math as their favorite subject. What percentage is this?
snow_lady [41]

Answer:

25%

Step-by-step explanation:

To find the percentage, we take the amount that found math as their favorite subject and divide it by the total amount of students.

33/132 = .25

This is in decimal form.  To change it to percent form, multiply by 100

.25 * 100 = 25 percent

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3 years ago
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"In order for a function to be one-on-one, no two elements of the domain may be paired with the same value of the range" True or
mariarad [96]
<span>In order for a function to be one-on-one, no two elements of the domain may be paired with the same value of the range is true 100%</span>
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4 years ago
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A triangle has sides with lengths of 6 inches, 13 inches, and 17 inches. Is it a right triangle?
Tems11 [23]

Answer:

Nope

Step-by-step explanation:

To now if a triangle is a right angle, use Pythagoras Theorem,

a^2 + b^2 = c^2

C usually be the longest side of the triangle, C = 17

Then also let a and b be 6 and 13 respectively.

6^2 + 13^2 =205

C^2 = 205

C = sqrt(205) = 14.32

therefore no this is not a right angle triangle

4 0
3 years ago
Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
Can you show us how to find the discriminant of the quadratic x^2 + 2x -2 =0
lorasvet [3.4K]
<em>Step #1: </em>
Make sure the equation is in the form of [ Ax² + Bx + C = 0 ].

Yours is already in that form.
A = 1
B = 2
C = -2

<em>Step #2:</em>
The 'discriminant' for that equation is [ B² - 4 A C ].
That's all there is to it, but it can tell you a lot about the roots of the equation.

-- If the discriminant is zero, then the left  side of the equation is a perfect square,
and both roots are equal. 

-- If the discriminant is greater than zero, the the roots are real and not equal.

-- If the discriminant is less than zero, then the roots are complex numbers.

The discriminant of your equation is  [ B² - 4 A C ] = 2² - 4(1)(-2) = 4 + 8 = 12

Your equation has two real, unequal roots.



4 0
3 years ago
Read 2 more answers
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