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polet [3.4K]
3 years ago
9

Can you show us how to find the discriminant of the quadratic x^2 + 2x -2 =0

Mathematics
2 answers:
vlabodo [156]3 years ago
6 0
the\ discriminant\ of\ the\ quadratic\ ax^2+bx+c=0\\\\\Delta=b^2-4\cdot a\cdot c\\-------------------------\\\\ x^2 + 2x -2 =0\\\\\Delta=2^2-4\cdot1\cdot(-2)=4+8=12\\\\discriminant=12
lorasvet [3.4K]3 years ago
4 0
<em>Step #1: </em>
Make sure the equation is in the form of [ Ax² + Bx + C = 0 ].

Yours is already in that form.
A = 1
B = 2
C = -2

<em>Step #2:</em>
The 'discriminant' for that equation is [ B² - 4 A C ].
That's all there is to it, but it can tell you a lot about the roots of the equation.

-- If the discriminant is zero, then the left  side of the equation is a perfect square,
and both roots are equal. 

-- If the discriminant is greater than zero, the the roots are real and not equal.

-- If the discriminant is less than zero, then the roots are complex numbers.

The discriminant of your equation is  [ B² - 4 A C ] = 2² - 4(1)(-2) = 4 + 8 = 12

Your equation has two real, unequal roots.



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Identify the equivalent expression for (m^1/3 m^1/5)^0
Lostsunrise [7]

Answer:

1.

Step-by-step explanation:

The thing is, x^0 is always 1. So even if you simplify, it will still be 1.

(m^\frac{1}{3}*m^\frac{1}{5})^0\\(m^\frac{8}{15})^0\\\text{But when put to the power of 0,}\\1.

4 0
2 years ago
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The question, Find the image vertices for a dilation with center (0, 0) and a scale factor of 4.
Alexeev081 [22]

Answer:

Answer is A(-3/4, 1/4), B(1,3/4), C(1/2,3/4) D(1/4,1)

Step-by-step explanation:

From the attached diagram, the coordinates are:

A(-3,1), B(4,-3), C(2,3), D(1,4)

The image is gotten by dividing the coordinates by the scale factor 4 to get the above answer

4 0
3 years ago
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
Here are two rectangles.
Sophie [7]

Answer:

AB=9.5\ cm

Step-by-step explanation:

step 1

Find the length side PQ

we know that

The area of rectangle PQRS is given by

A=(PQ)(QR)

A=66\ cm^2

so

66=(PQ)(QR)

substitute the value of QR

66=(PQ)(12)

solve for PQ

PQ=66/12\\PQ=5.5\ cm

step 2

Find the length side AB

we know that

The perimeter of rectangle ABCD is given by

P=2(AB+BC)

we have

P=30\ cm\\BC=PQ=5.5\ cm

substitute

30=2(AB+5.5)

solve for AB

15=AB+5.5\\AB=15-5.5\\AB=9.5\ cm

6 0
3 years ago
Which equation listed below, when solved, shows how to find the circumference of a circle if the diameter is 6 inches? Use 3.14
dangina [55]

Answer:

C = π(6)

C = 6π

C = 18.84

Step-by-step explanation:

The circumference is the distance around the circle. It relates the number of times the diameter will encircle the circumference as 3.14 or π. As a result, the formulas for the circumference of a circle are C = 2πr or C = πd. The information given is the diameter so use C = πd by substituting d = 6.

C = π(6)

C = 6π

C = 18.84

6 0
2 years ago
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