We are given that the system “releases” heat of 2,500 J,
and that it “does work on the surroundings” by 7,655 J.
The highlighted words releases and does work on the surroundings
all refers to that it is the system itself which expends energy to do those
things. Therefore the action of releasing heat and doing work has both magnitudes
of negative value. Therefore:
heat released = - 2, 500 J
work done = - 7, 655 J
Which means that the total internal energy change of the
system is:
change in internal energy = heat released + work
<span>change in internal energy = - 2, 500 J + - 7, 655 J</span>
<span>change in internal energy = -10,155 J</span>
2) b) The height above the surface of the earth
3) b) air pressure differences that make air rise or sink
4) a) TC (I'm not sure about this)
5) I don't know this one. Sorry :(
6) a) true
7) a) true
8) b) false (I'm not sure about this)
Sorry I couldn't answer all your questions, but I hope this helps!
B) initial speed (u)=3
final speed (v)=8
time (t)= 10
acceleration (a)=?
v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²
c)displacement (s)=?
1st section of journey
v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters
2nd section of journey
a=0
t=7
u=8
s=?
s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters
56+55= 111 meters
(For graph x axis =time (sec) & y axis= velocity (m/s))