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AfilCa [17]
3 years ago
15

Can you provide the answer for me? It’s number 4

Physics
1 answer:
Sever21 [200]3 years ago
3 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

<u>Question</u> 4 : 770 mm Hg = how many pascals

<u>C</u><u>onversion from mm Hg to atm</u> :

  • 760 mm Hg = 1 atm

  • 1 mm Hg = 1 / 760 atm

  • 770 mm Hg = (1 / 760) × 770 atm

  • 770 mm Hg = 1.013 atm

<u>Conversion from atm to kPa</u> :

  • 1 atm = 1.013 × 10² kPa

  • 1.013 atm = 1.013 × 1.013 × 10² kPa

  • 1.013 atm = 1.026 × 10² kPa

<u>Conversion of kPa to Pa</u> :

  • 1.013 atm = 1.026 × 10² × 10³ Pa

  • 1.013 atm = 1.026 × 10⁵ pascals

hence, 770 mm Hg = 1.026 × 10⁵ Pa

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son4ous [18]
Some scientist believe that the ozone layers of the earth had been weakening and the waters or current changes direct ever 5-7 month.
7 0
3 years ago
At cruise conditions, air flows into a jet engine at a steady rate of 60 lbm/s. Fuel enters the engine at a steady rate of 0.59
Amanda [17]

Answer:

ρ=0.0102lbm/ft^3

Explanation:

To solve this problem we must take into account the equation of continuity, this indicates that the sum of the mass flows that enter a system is equal to the sum of all those that leave.

Therefore, to find the mass flow of exhaust gases we must add the mass flows of air and fuel.

m=0.59+60=60.59lbm/s( mass flow of exhaust gases)

The equation that defines the mass flow (amount of mass that passes through a pipe per unit of time) is as follows

m=ρVA

Where

ρ=density

V=velocity

m=mass flow

A=cross-sectional area

solving for density

ρ=m/VA

ρ=60.59/{(1485)(4)}

ρ=0.0102lbm/ft^3

8 0
3 years ago
The 1000-lb elevator is hoisted by the pulley system and motor M. If the motor exerts a constant force of 500 lb on the cable, d
Nezavi [6.7K]

Answer:

the power that must be supplied to the motor is  101.45 hp

Explanation:

Given that,

The weight of elevator = 1000lb

The motor exerts a constant force of 500 lb on the cable

The load has been hoisted s = 15 ft starting from rest

The motor has an efficiency of e = 0.65

According to the equation of motion:

F = ma

3(500) - 1000 = \frac{1000}{32.2} * aa = 16.1 ft/s^2

v^2 - u^2 = 2a (S - So)\\\\v^2 - (0)^2 = 2 * 16.1 (15-0)\\\\v = 21.98m/s

To calculate the output power:

P(out) = F. v

P(out) = 3 (500) * 21.98

P(out) = 32970 lb.ft/s

As efficiency is given and output power is known, we can calculate the input power.

ε = P(out) / P(in)

0.65 = 32970 / P(in )

P(in) = 50,723 lb.ft/s

P(in) =  50,723 / 500 hp

    = 101.45 hp

the power that must be supplied to the motor is  101.45 hp

5 0
3 years ago
A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8
mylen [45]

Answer:

f = 2.6 \times 10^{-13}

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

N = \frac{m}{29} \times 6.02 \times 10^{23}

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

N_e = m(6.02 \times 10^{29})

now diameter of the ball is 7.0 mm

density of the ball = 8900 kg/m^3

now we have

m = (\frac{4}{3}\pi r^3)(8900)

m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)

m = 1.6 gram

now we have

N_e = 9.63 \times 10^{23}

now the charge on the copper ball is 40 nC

so the number of electrons removed

Q = ne

40 \times 10^{-9} = n(1.6 \times 10^{-19}

n = 2.5 \times 10^{11}

so the fraction of number of electrons removed is given as

f = \frac{n}{N_e}

f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}

f = 2.6 \times 10^{-13}

7 0
3 years ago
Which is NOT considered as a property of electromagnetic waves: 5
OlgaM077 [116]

Answer:

require a medium to propagate

Explanation:

this is because electromagnetic waves can travel through vacuum at the speed of 3.0 x 10^8 m/s

because they don't need particles to transfer energy

hope this helps

4 0
3 years ago
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