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AfilCa [17]
3 years ago
15

Can you provide the answer for me? It’s number 4

Physics
1 answer:
Sever21 [200]3 years ago
3 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

<u>Question</u> 4 : 770 mm Hg = how many pascals

<u>C</u><u>onversion from mm Hg to atm</u> :

  • 760 mm Hg = 1 atm

  • 1 mm Hg = 1 / 760 atm

  • 770 mm Hg = (1 / 760) × 770 atm

  • 770 mm Hg = 1.013 atm

<u>Conversion from atm to kPa</u> :

  • 1 atm = 1.013 × 10² kPa

  • 1.013 atm = 1.013 × 1.013 × 10² kPa

  • 1.013 atm = 1.026 × 10² kPa

<u>Conversion of kPa to Pa</u> :

  • 1.013 atm = 1.026 × 10² × 10³ Pa

  • 1.013 atm = 1.026 × 10⁵ pascals

hence, 770 mm Hg = 1.026 × 10⁵ Pa

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initial velocity of the object falling down, v = 10 m/s

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v = u + at

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A 2.00-kg object A is connected with a massless string across a massless, frictionless pulley to a 3.00-kg object B. Object A re
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Answer:

  • tension: 19.3 N
  • acceleration: 3.36 m/s^2

Explanation:

<u>Given</u>

  mass A = 2.0 kg

  mass B = 3.0 kg

  θ = 40°

<u>Find</u>

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<u>Solution</u>

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  F = mg·sin(θ) = (2 kg)(9.8 m/s^2)(0.642788) = 12.5986 N

Mass B is being pulled downward by gravity with a force of ...

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The tension in the string, T, is such that the net force on each mass results in the same acceleration:

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  T = (2(29.4) +3(12.5986))/5 = 19.3192 N

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Then the acceleration of B is ...

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The string tension is about 19.3 N; the acceleration of the masses is about 3.36 m/s^2.

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