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3 years ago

The object will feel minimum force of gravity at the

Physics

2 answers:

vlada-n [284]3 years ago

6 0

Answer:

Poles

Explanation:

The gravitational force is maximum at the equator and minimum at the poles.

Alika [10]3 years ago

4 0

Answer:

space , small amount of gravity is found in the space ,infact we can say that there is no gravity in the space

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A Force of 20N displaces a body about 45m how much work is done?

Orlov [11]

Answer:

159 ofc

Explanation:

7 0

3 years ago

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A spring scale hung from the ceiling stretches by 6.1cm when a 2.0kg mass is hung from it. The 2.0kg mass is removed and replace

Anarel [89]

2.0kg and the mass of sometimes makes it hard 2.8kg

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3 years ago

Unpolarized light is incident upon two ideal polarizing filters that do not have their transmission axes aligned. If 14% of the

vladimir1956 [14]

Answer:

A) 58 degree

Explanation:

When unpolarized light passing through first polarizer then the intensity of light becomes half as it will get polarized

So let say the intensity of unpolarized light is "Io" then after passing through first polarizer the intensity will become half

Now when this polarized light passing through another polarizer then the intensity of light is given by Malus law

As per Malus law if the angle between two polarizer axis is inclined at some angle

then it is given as

$I = I_0 cos^2\theta$

$0.14I_0 = 0.5I_0cos^2\theta$

$0.28 = cos^2\theta$

$\theta = 58 degree$

6 0

3 years ago

A tradesman sharpens a knife by pushing it with a constant force against the rim of a grindstone. The 30-cm-diameter stone is sp

Lorico [155]

Answer:

a. 0.21 rad/s2

b. 2.205 N

Explanation:

We convert from rpm to rad/s knowing that each revolution has 2π radians and each minute is 60 seconds

200 rpm = 200 * 2π / 60 = 21 rad/s

180 rpm = 180 * 2π / 60 = 18.85 rad/s

r = d/2 = 30cm / 2 = 15 cm = 0.15 m

a)So if the angular speed decreases steadily (at a constant rate) from 21 rad/s to 18.85 rad/s within 10s then the angular acceleration is

$\alpha = \frac{\Delta \omega}{\Delta t} = \frac{21 - 18.85}{10} = 0.21 rad/s^2$

b) Assume the grind stone is a solid disk, its moment of inertia is

$I = mR^2/2$

Where m = 28 kg is the disk mass and R = 0.15 m is the radius of the disk.

$I = 28*0.15^2/2 = 0.315 kgm^2$

So the friction torque is

$T_f = I\alpha = 0.315*0.21 = 0.06615 Nm$

The friction force is

$F_f = T_f/R = 0.06615 / 0.15 = 0.441 N$

Since the friction coefficient is 0.2, we can calculate the normal force that is used to press the knife against the stone

$N = F_f/\mu = 0.441/0.2 = 2.205 N$

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3 years ago

Of the eight most abundant elements in earths crust, what percentage does the six next most abundant elements of earths crust ma

Mrac [35]

Answer:

the sixth most abundant element in the earth's crust is sodium and it occupies 2.8%

5 0

3 years ago