K/3 + 4 -2k = -9k
First you add 9k to both sides
<span>k/3 + 4 -2k = -9k
</span> +9k +9k
<span>k/3 + 4 + 7k = 0
</span>
Now subtract 4 from both sides
k/3 + 4 + 7<span>k = 0
</span> -4 -4
k/3 + 7<span>k = -4
</span>
Now multiply 3 by both sides
k/3 + 7<span>k = -4
</span>x3 x3 x3
k +21k = -12
Now add k + 21k
22k = -12
Now divide both sides by 22
<span>22k = -12
</span>----- -----
22 22
k = -6/11
Answer: 9
Step-by-step explanation:
4x²-7x+7 f(2)=4*(2)^2-7(2)+7=16-14+7=9
Answer:
Sure but can you show me the triangle.
0.32 centavos, Dividí 3.89 por 12, y obtuve 0.32 centavos después de redondear la respuesta por décimas.
Answer:
In order to minimize cost the outlet must order 60 units 15 times a year.
Explanation:
Theoretically, the EOQ is the optimal order quantity that a firm should purchase in order to minimize its inventory costs (holding costs are included here), and costs of placing an order.
Mathematically:
EOQ= 
Where:
D= demand
S= cost of placing an order.
H= holding cost (per unit and per year).
In the statement, we identify each of these values:
D= 900
S= 4
H= $2
EOQ=
=√2*4*900/2= 60
Times per year= 900/60= 15