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sasho [114]
3 years ago
10

The capacity of a syringe is 0.08 liters. Convert this to milliliters.

Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

80 millilitres (mL)

Step-by-step explanation:

Multiply by 1000 because there are 1000 mL in 1 L

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In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
En una casa de empanadas hornean 1.200 por día. Si las cocinan en fuentes de 75 unidades, colocando siempre la mayor cantidad po
valkas [14]

Answer:

16 unidades preparan simultáneamente 1200 empanadas por día.

Step-by-step explanation:

Si cada fuente tiene una capacidad de 75 empanadas por horneada y que la mayor cantidad posible ocurre cuando el volumen de producción se cocina simultáneamente, entonces el total de fuentes es la cantidad total de producción dividida por la capacidad de empanadas por fuente. Es decir:

x = \frac{1200\,emp}{75\,\frac{emp}{und} }

x = 16\,unidades

16 unidades preparan simultáneamente 1200 empanadas por día.

3 0
3 years ago
Problem Solving<br> Help
Yuri [45]
1 quart is 2 pints so 1 would be 2 would be 4 3would be 6 etc so for the graphs the coordinates would be (1,2) (2,4) (3,6) etc..
4 0
2 years ago
Read 2 more answers
The cylinder above has a radius of 5 inches and a height of 12 inches. What is the surface of the cylinder above?
Ipatiy [6.2K]

Answer:

I think its b

Step-by-step explanation:

A=2πrh+2πr2=2·π·5·12+2·π·52≈534

5 0
3 years ago
The length of a rectangle is 16 feet more than three times the width. The perimeter of the rectangle is 248 feet. Find the dimen
sattari [20]

Answer:

L = 97, w = 27

Step-by-step explanation:

The perimeter formula is P = 2L + 2w.  We have too many unknowns simply to plug in, so we have to find a way to identify one in terms of the other.  The statement is that the length is 16 feet more than 3 times the width, so the length is in terms of the width and can be identified as

L = 3w + 16

and the width, then, is just w.  Now we can fill in those 2 values, both in terms of w, and set it to equal the perimeter value we were given of 248:

2(3w + 16) + 2w = 248 and

6w + 32 + 2w = 248 and

8w + 32 = 248 and

8w = 216 so

w = 27

That means that the width is 27.  Use that value of w now to find the length where

L = 3w + 16.

L = 3(27) + 16 and

L = 97

6 0
3 years ago
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