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navik [9.2K]
3 years ago
11

Please help No links please Answer the question in the picture

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
The 1st one


I need to put more words
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Can some one please help me?
lesya [120]
Height:shadow
so 3.5:1.06 and is the same as 50.5:x
we treat it as a fraction and get
3.5/1.06 and x/50.5

they should be equal
we know that if we multiply two equal fractions, with one flipped, then we will get 1 exg 1/2=4/8    1/2 times 8/4=8/8=1

so 3.5/1.06=x/50.5    3.5/1.06 times 50.5/x=1
176.75/1.06x=1
multiply both sides by 1.06x
176.75=1.06x
divide both sides by 1.06
166.745=x
round up to hundreds place
166.75m=accutal height
4 0
3 years ago
explain why the graph of the function y = 3x + 40 will never intersect the graph of the function y = 3x + 35 .
AlladinOne [14]
These two graphs have the same slope (3), and are therefore parallel. Parallel lines never intersect each other.
4 0
4 years ago
Two mechanics worked on a car.The first mechanic charged $85 per hour, andthe second mechanic charged $70 per hour.The mechanics
KATRIN_1 [288]
70x+85(20-x)=1625
Solve for x
X=5 for 70

X=15 for 85
5 0
3 years ago
Reduce24/3 to lowest terms
denpristay [2]
" / " this means divide, so if your dividing it is 8 because 8 times 3 is 24
5 0
3 years ago
Find the length of l on the curve r(t)=5cos(3t)i-5sin(3t)j+3tk over the interval [3,7]
stealth61 [152]
\mathbf r(t)=5\cos3t\,\mathbf i-5\sin3t\,\mathbf j+3t\,\mathbf k
\mathrm d\mathbf r(t)=\mathbf r'(t)\,\mathrm dt=(-15\sin3t\,\mathbf i-15\cos3t\,\mathbf j+3\,\mathbf k)\,\mathrm dt

\displaystyle\int_C\mathrm d\mathbf r(t)=\int_{t=3}^{t=7}\|\mathbf r'(t)\,\mathrm dt\|=\int_{t=3}^{t=7}\sqrt{225\sin^23t+225\cos^23t+9}\,\mathrm dt
=\displaystyle3\sqrt{26}\int_{t=3}^{t=7}\mathrm dt
=12\sqrt{26}
4 0
4 years ago
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