Answer:
The 99% of a confidence interval for the average maximum HP for the experimental engine.
(536.46, 603.54)
Step-by-step explanation:
<u><em>Step:-1</em></u>
Given that the mean of the Population = 540HP
Given that the size of the sample 'n' = 9
Given that the mean of the sample = 570HP
Given that the sample standard deviation = 30HP
<u><em>Step(ii):-</em></u>
<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>
<u><em>t₀.₀₀₅ = 3.3554</em></u>
The 99% of a confidence interval for the average maximum HP for the experimental engine.
(570 - 33.54 , 570+33.54)
(536.46 , 603.54)
<u><em>Final answer</em></u> :-
<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>
<em>(536.46, 603.54)</em>
<em></em>
Answer: 46 or 46=4
Step-by-step explanation:
Do what's in the Parenthesis first so 7+2=10 which now give you the equation
[10x 5-4]=2+2
Now we Multiply so we do 10x5 which is 50 so that now gives us the equation[50-4]=2+2
Now we add the 2+2 which is 4 giving us the equation [50-4]=4
Now we subtract 50-4 giving 46
46=4
Answer:
482
Step-by-step explanation:
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9514 1404 393
Answer:
[[274][895][136]]
Step-by-step explanation:
Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.
The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.
There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.
The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.
Our solution is ...
row 1: 2 + 7 × 4 = 30
row 2: 8 + 9 × 5 = 53
row 3: 1 × 3 - 6 = -3
And that makes the column equations be ...
col 1: 2 - 8 + 1 = -5
col 2: 7 + 9 / 3 = 10
col 3: 4 × 5 - 6 = 14
The change of the cost changes when the pounds of ham changes. When the pounds of ham is 0, it costs 0 dollars. When the pounds of ham is 3, it costs 12 dollars. The cost changes consistently with the pounds of ham. They change together. Every time the pounds of ham goes up by 3, the cost goes up by 12.
