Ask question

Ask question

All categories

3 years ago

13

A company made a profit of $75,000 over a period of 6 years on an initial investment of $15,000. What is its annualized ROI? 26%

66.67% 83.33%

2 answers:

Mamont248 [21]3 years ago

6 0

<span>ROI = $12,500/$15,000 or 83.3%</span>

allsm [11]3 years ago

4 0

Annual ROI is approximately 83.3%

Find annual profit: $75,000/6 = $12,500

ROI = Annual Profit/ initial investment
ROI = $12,500/$15,000 or 83.3%

You might be interested in

Suppose a triangle has two sides of length 33 and 37 and that the angle between these two sides is 120 what is the length of the

Nutka1998 [239]

Answer:

60.65

Step-by-step explanation:

The Law of Cosines can help you figure this out. Call the given sides "a" and "b" and the given angle "C". Then the third side, "c" will satisfy the relation ...

c² = a² + b² -2ab·cos(C)

= 33² +37² -2·33·37·cos(120°) = 3679

c = √3679 ≈ 60.65476 ≈ 60.65

The length of the third side is about 60.65 units.

5 0

3 years ago

Write an equation of the line that passes through (5,9) and is perpendicular to the line y=-1/3x+1

777dan777 [17]

Perpendicular = opposite sign and reciprocal slope
Slope would be 3
Y = 3x + b, plug in point
9 = 3(5) + b, b = -6
Solution: y = 3x - 6

7 0

2 years ago

Consider the following function. F(x)=3/2+4 Using the given function, plot all the ordered pairs for the values in the domain be

Butoxors [25]

I can't edit pictures for you so as a result I can't answer it. But label those numbers on the x line and that will be your answer. And OMG your laptop is torn up I tell you TORN.

8 0

3 years ago

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

8 0

3 years ago

What is 4/3 π multiplied by 2

shusha [124]

0.84882636315
the answer

5 0

2 years ago

Read 2 more answers