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3 years ago

SOMEONE PLSSSS HELP ME WITH THIS QUESTION!!!

Mathematics

1 answer:

Doss [256]3 years ago

3 0

Answer:

12% males do not commute to work daily

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Hello!! Please help me solve the question, could you please also tell me which calculator we can use? Thank you

Gwar [14]

You can use any calculator in Maths.

7 0

3 years ago

Hey can you please help me posted picture of question

Zinaida [17]

The inverse functions have a property that the composition of two inverse functions always results is x.

From the given options, only the pair given in option B result in the composition equal to x.

$F(x)= \frac{12}{x}-18 \\ \\ 
G(x)= \frac{12}{x+18} \\ \\ 
F(G(x))= \frac{12}{ \frac{12}{x+18} }-18 \\ \\ 
F(G(x))= \frac{12(x+18)}{12}-18 \\ \\ 
F(G(x))=x+18-18=x$

This proves, F(x) and G(x) are inverse of each other.

So the answer to this question is Option B

7 0

3 years ago

Factor the expression 6p^3-12p^2+9p

Kazeer [188]

Answer:

3p(2p^2-4p+3)

Step-by-step explanation:

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3 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

goldfiish [28.3K]

The triangles can be proven using the SAS postulate. The congruency statement is CAM is congruent to IAM (sorry I don’t know how to type the congruent sign).

3 0

3 years ago

If an initial amount A0 of money is invested at an interest rate i compounded times a year, the value of the investment after t

seropon [69]

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

$\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}$

In point 1:

$\to y = (1+ \frac{r}{n})^{nt}$

In point 2:

$\to \ln (y)= nt \ln(1+ \frac{r}{n})$

In point 3:

Its key thing to understand, which would be that you consider the limit n to $\infty$ , in which r and t were constants!

$=lim_{n \to \ \infty} \ln (y) = lim_{n \to \ \infty} nt \ln(1+\frac{r}{n})\\\\= lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\= lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\= lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\= lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt$

In point 4:

$\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt}$ and

$\to \lim_{n \to \ \infty} = A_0e^{rt}$

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3 years ago