Recall your d = rt, distance = rate * time
one car is going at 55kph, at say hmmm "t" time
the second car zooms by at 75kph, an hour later, thus " t + 1 "
notice, overtaking the 1st car, simply means, the second car comes from behind approaches the first car from behind and "gets there", at that very second, both cars have travelled a distance, say "d"
if the first car travelled "d" kilometers
for the second car to "get there" has to had travelled "d" distance as well

solve for "t"
Okay so we just need to find out the pattern...
in this case the pattern is adding..
we did
1 + 4 = 5
2 + 5 = 12
we figure this one out by adding 2 and 5 twice so it look like this
2 + 5 + 5 = 12
now moving on to our next one
3 + 6 = 21
so we added 3 and added 6, three times so look
3 + 6 + 6 + 6 = 21
so now
8 + 11 = 96 because we added 8 and added 11, eight times look..
8 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 = 96
so our answer to 8 + 11 is 96!
hope this helps:)
and don't forget 2
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Answer:
No, it is not.
Step-by-step explanation:
This is because if you look at the expression, there is no term that is raised to the cube root. As a result, this isn't a cubic polynomial. However, this would be a quadratic polynomial cause the highest raised exponent is 2, which is the number for quadratic.
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Answer:
h(x)
h(x)
f(x) g(x) h(x)
Step-by-step explanation:
Edge 2020
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