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3 years ago

Between what two numbers would 9 be located on a number line?

Mathematics

2 answers:

lilavasa [31]3 years ago

7 0

Answer:

Step-by-step explanation:

the between of two bumber of 9 is 8 & 10 8<9<10

Mariulka [41]3 years ago

5 0

$it \: is \: simple \\ between \: 8 \: \: \: 10$

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(PLEASE ANSWER) Drag numbers to complete the equation and find the area of the parallelogram.

8_murik_8 [283]

Answer:

A= 12· <u>8</u>

= <u>96</u> m²

Step-by-step explanation:

4 0

3 years ago

I need help ASAP please

zhenek [66]

Answer:

48x + 216 square inches.

Step-by-step explanation:

Area is length X width.

Area is (4x + 18)(12).

in 4x + 18, 18 comes from adding the three 6 in.

We have no values for "x", so expand the equation and simplify.

(4x + 18)(12)

= 48x + 216

6 0

3 years ago

Is 10^5 an exponents for 100,000

Masja [62]

Yes, because 10 x 10 x 10 x 10 x 10 (which equals 10^5) is equal to 100,000.
Remember, 10 to the power of anything (like 8, 5, or 9) just means that you have to count out however many zeros the exponent tells you to, which in this case, is five.

8 0

4 years ago

1/4, 3/4, 5/4, 7/4, ... 15th term

Crazy boy [7]

Answer:

29/4

Step-by-step explanation:

2/4 is added per step

14 steps from 1/4

1/4 + 14.(2/4) = 29/4

5 0

3 years ago

Read 2 more answers

What is a simlified form of x+3 over x^2-x-12 multiplied by x-4 over x^2-8x+16?

Vesnalui [34]

Answer:

$\large\boxed{\dfrac{x+3}{x^2-x-12}\cdot\dfrac{x-4}{x^2-8x+16}=\dfrac{1}{x^2-8x+16}}$

Step-by-step explanation:

$\dfrac{x+3}{x^2-x-12}\cdot\dfrac{x-4}{x^2-8x+16}=\dfrac{x+3}{x^2+3x-4x-12}\cdot\dfrac{x-4}{x^2-8x+16}\\\\=\dfrac{x+3}{x(x+3)-4(x+3)}\cdot\dfrac{x-4}{x^2-8x+16}=\dfrac{x+3}{(x+3)(x-4)}\cdot\dfrac{x-4}{x^2-8x+16}\\\\\text{cancel}\ (x+3)\ \text{and}\ (x-4)\\\\=\dfrac{1}{x^2-8x+16}$

6 0

3 years ago