Question 4(Multiple Choice Worth 5 points) Simply: -2 1/3-(-10 1/6)

Which point is on the line that passes through point R and is perpendicular to line PQ? (–6, 10) (–4, –8) (0, –1) (2, 4)

Paraphin [41]

Answer:

(-4, -8)

Step-by-step explanation:

Let the coordinates of common point of the given lines are (x, y),

Thus, the slope of the line passes through the points (a, b) and R(4,2) is,

2 - b

m1 = ------

4 - a

Again, the slope of the line passes through two points P(-6,4) and Q(4,-4),

-4 - 4 -8 -8 -4

m2 = ------ = --------- = --------- = ---------

4- (-6) 4 + 6 10 5

= m1 * m2 = -1

2 - b -4

= ------- x ---- = -1

4 - a 5

8 - 4b

= ----------- = 1

20 - 5a

= 8 - 4b = 20 - 5a

= 5a - 4b = 12 --------- equation 1

For a = -6 and b = -10

5 x -6 - 4 x 10 = -70 ≠ 12

For a = -4 and b = -8

5 x -4 - 4 x - 8 = 12 = 12

For a = 0 and b = -1

5 x 0 - 4 x -1 = 4 ≠ 12

For a = 2 and b = 4

5 x 2 - 4 x 4 = -6 ≠ 12

therefore Second is correct

hope it helps and i get the brainliest.

4 0

4 years ago

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Sasha has 6 packages of balloons, each with 7 balloons. She opens one

Lynna [10]

Answer: Sasha has 39 balloons

Step-by-step explanation:

6 x 7 = 42

42-3 = 39

4 0

3 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0

3 years ago

3. There are four teams in the raquetball league on the island of Allendine. In a season, they play each other once. Three point

andrew-mc [135]

Answer and Step-by-step explanation:

Team: Points. Results fetching points

Arcadia. 3+1. 1 win & 1 draw

Brextone. 3+1. 1 win & 1 draw

Cremore 1+1. 2 draws

Dunross. 3+3. 2 wins

a) Based on the previous data, we can conclude that the number of matches drawn was 4

b) Dunross defeated cremore since cremore did not win any league game and dunross reported no ties

c) Yes, you can get a prediction of the matches with their respective results as follows

Brextone drew with Cremore

Dunross beat Arcadia

Arcadia beat Brextone

Arcadia drew with Cremore

Dunross beat Cremore

7 0

4 years ago

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PLEASE HELP IM STUCK

SpyIntel [72]

Step-by-step explanation:

$\frac{y2 - y1 }{x2 - x1} = \frac{3 - - 2}{5 - 0} = \frac{5}{5} = 1$

4 0

2 years ago

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