Người ta ước tính rằng sau t năm tính từ bây giờ, dân số ở một vùng ngoại ô sẽ là P(t)=20-6/t+1 nghìn người
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We have the data set:
{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}
This data set has 10 items.
To complete the data summary is helpful to sort the data:
{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}
The minimum value is 72.
<em>The quartile divides the data set in 4 parts. </em>
<em>The first quartile is the value for which 25% of the data is below.</em>
<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>
<em>The third quartile is the value for which 75% of the data is below.</em>
In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.
The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.
This values are 73 (2nd position) and 77 (3rd position), so the average is:
We can repeat this with the other quartiles:
Then:
The first quartile is 75.
The median (second quartile) is 79.
The third quartile is 82.
The maximum value is 83.
Answer:
Evergreen Eagle can will fly 1.56 km in 20 minutes.
Step-by-step explanation:
Speed of Evergreen Eagle =
=
= 13 meters per second
With this speed Eagle can fly the distance in 20 minutes Or 120 seconds
= Speed × Time
= 13 × 120
= 1560 meters
Since, 1000 meters = 1 Km
1 meter = km
Therefore, 1560 meters =
= 1.56 km
Therefore, Evergreen Eagle can will fly 1.56 km in 20 minutes.