1200, (2)3+(2)2+2 = 6+4+2 = 12 12(100)= 1200
Answer:
Starting from the left.
4 × 3
5 × 5
2 × 5
4 × 5
4 × 4
1.5 × 2
Step-by-step explanation:
Divide all dimensions by 8.
Kylie's first month collection, a1= $ 145
Second month collection , a2= $145+ 20
Third month collection, a3 = $145 +2*20
.
.
.
.
so for n months collection = an-1+20
We get an= 20 + an-1 and a1=145
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
