For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
The answer is y equals 0.85 x. Hope this help you
Step-by-step explanation:
Lets begin with this 4x-25=x+14, 3x=39, so x=13, than we plug it in to side NP because that is the most simple one to plug it into to and that side is 27 since the triangle is equilateral all sides are the same so it is 27, 27, 27, for the sides and x=13
Answer:
The answer is 3
Step-by-step explanation:
The answer is 3 because the number with x is always the slope.
Check the picture below.
so the <u>triangular prism</u> is really 3 rectangles and two triangles stacked up to each other at the edges, so if we simply get the area of each figure individually and sum them up, that's the area of the prism.
let's notice, the triangles have a base of 2.4 and a height/altitude of 1.
![\bf \stackrel{\textit{2 triangles's area}}{2\left[ \cfrac{1}{2}(2.4)(1) \right]}~~+~~\stackrel{\textit{right rectangle}}{(2\cdot 1.5)}~~+~~\stackrel{\textit{left rectangle}}{(2\cdot 1.7)}~~+~~\stackrel{\textit{bottom rectangle}}{(2\cdot 2.4)} \\\\\\ 2.4+3+3.4+4.8\implies 5.4+8.2\implies 13.6](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B2%20triangles%27s%20area%7D%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.4%29%281%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bright%20rectangle%7D%7D%7B%282%5Ccdot%201.5%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bleft%20rectangle%7D%7D%7B%282%5Ccdot%201.7%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bbottom%20rectangle%7D%7D%7B%282%5Ccdot%202.4%29%7D%20%5C%5C%5C%5C%5C%5C%202.4%2B3%2B3.4%2B4.8%5Cimplies%205.4%2B8.2%5Cimplies%2013.6)
