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4 years ago

8

Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0. 36y'' − y = x

ex/6

1 answer:

viktelen [127]4 years ago

5 0

Try this solution, note, checking was not performed.

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What is804,082 in expanded form

Nutka1998 [239]

800000+4,000+80+2 you don’t need the zeros

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4 years ago

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Give an example of both rational and an irrational number that falls between 24 and 25

levacccp [35]

Both 24 and 25 are rational. They can be turned into a fraction by putting a 1 as the denominator.

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3 years ago

PLZ HELP QUICKLY!<br> Find the value of the expression.<br> 10^2

blagie [28]

Answer:

100 is correct answer

Step-by-step explanation:

${10}^{2} \\ = 10 \times 10 \\ = 100$

when ever anything ² , it means that number is multiplied by itself.

in above we multiple 10 with 10 and we get 100.

hope it helped you:)

8 0

3 years ago

By selling a cow for Rs 144, there is a profit of the same percentage as its cost price. Find the cost price.

hjlf

Answer:

Step-by-step explanation:

<h2><u>☼︎</u><u>Answer:</u></h2>

The cost price of cow = Rs.80

Explanation:

<h2><u>☼︎</u><u>Given :-</u></h2>

By selling a cow for Rs 144, there is a profit of the same percentage as its cost price.

<h2><u>☼︎</u><u>T</u><u>o Find</u><u>:</u><u>-</u></h2>

The cost price.

<h2 /><h2 /><h2><u>☼︎</u><u>L</u><u>e</u><u>t</u><u>:</u><u>-</u></h2>

The cost price of cow = Rs.x

<h2><u>☼︎</u><u>Solution :-</u></h2>

$\sf x + x \: of \: x\%= 144 \\ \\ \sf \implies x + \frac{x \times x}{100} = 144 \\ \\ \sf \implies {x}^{2} + 100x - 14400 = 0 \\ \\ \sf \implies x(x - 80) + 180(x - 80) = 0 \\ \\ \sf \implies x + 180 = 0 \\ \\ \sf \implies x = - 180 \\ \\ \sf \therefore \: {\boxed{ \sf \pink{x = 80}}}$

<h2><u>Hence: </u></h2>

The cost price of cow =<u>R</u><u>s</u><u>8</u><u>0</u>

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3 years ago

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What are Two equations that model this relationship 5:25

JulijaS [17]

Answer:

5/25 and 5 to 25

Step-by-step explanation:

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4 years ago