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3 years ago

8

Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0. 36y'' − y = x

ex/6

1 answer:

viktelen [127]3 years ago

5 0

Try this solution, note, checking was not performed.

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3 years ago

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3 years ago

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3 years ago

Plz help me out with this

nadya68 [22]

Given,

HK is the perpendicular bisector of GJ. So, <u>GK = KJ</u>.
GK = 2x + 10
KJ = 3x - 15

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Find KJ .

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First find the value of x

$\sf \: GK \: = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x = - 15 - 10 \\ \sf - x = - 25 \\ \sf \: - > \boxed{\bf \: x = 25}$

Now, find the value of KJ.

$\sf3x - 15 \\ \sf= 3(25) - 15 \\ \sf=7 5 - 15 \\ = \boxed{\bf \: 60}$

-> The value of KJ is <u>6</u><u>0</u><u>.</u>

_______________

Hope it helps.

RainbowSalt2222

6 0

3 years ago

Read 2 more answers