Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0. 36y'' − y = x
ex/6
1 answer:
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We are to find the value of 
First we evaluate tan(π/4). The value of tan(π/4) is 1.
So,
sin(π/2) = 1
So,
Thus, we can write:
radians.
So, the answer to this question is π/2 radians.
First we evaluate tan(π/4). The value of tan(π/4) is 1.
So,
sin(π/2) = 1
So,
Thus, we can write:
So, the answer to this question is π/2 radians.
