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3 years ago

Let g(x)=x-3 and h(x)=x^2+6 find (h o g) (1)

Mathematics

2 answers:

cupoosta [38]3 years ago

5 0

$g(x)=x-3 \ \ \ and\ \ \ h(x)=x^2+6 \\\\(h \circ g) (1)=h\bigg (g(1)\bigg)=h\bigg(1-3\bigg)=h(-2)=(-2)^2+6=4+6=10$

Rudiy273 years ago

5 0

$h \circ g=(x-3)^2+6=x^2-6x+9+6=x^2-6x+15$

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Write a fraction to represent the division in each situation. ; Jason plans to pay the water bill with two equal payments. Water

xenn [34]

9514 1404 393

Answer:

$35/2

Step-by-step explanation:

Division by 2 is indicated by putting 2 in the denominator of the fraction:

35/2

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2 years ago

There are 50 cupcakes and 160 cookies to be sold at the school bake sale. What is the greatest number of packages of baked items

Sav [38]

The greatest number of packages of baked items that can be sold is 10

Solution:

Given that there are 50 cupcakes and 160 cookies to be sold at the school bake sale

To find: greatest number of packages of baked items that can be sold

Each package has the same number of cupcakes and same number of cookies with none left over

So, we have to find the greatest common factor of 50 and 160

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

Greatest common factor of 50 and 160:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 160 are: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160

Then the greatest common factor is 10

So the greatest number of packages sold is 10

Each package will contain:

Given that there 50 cupcakes and 160 cookies

Number of cupcakes in 1 package:

$\rightarrow \frac{50}{10} = 5$

Number of cookies in 1 package:

$\rightarrow \frac{160}{10} = 16$

So each package has the same number of cupcakes and same number of cookies with none left over

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4 years ago

Find the area.. of the figure below...

RoseWind [281]

Answer:

Step-by-step explanation:

rectangle 8

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3 years ago

How do I solve 3(x+5)=39

azamat

3(x+5)=39

3 * x + 3 * 5 = 39

3x + 15 = 39

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3 years ago

Read 2 more answers

Find all roots. 11) x^3 + 6x² + 5x = 0

Dmitrij [34]

Answer:

x=0

x=-1

x=-5

Step-by-step explanation:

To find the roots, we set the equation equal to zero and factor.

x(x²+6x+5)=0 [factor]

x(x+1)(x+5)=0 [set each factor equal to 0]

x=0

x+1=0 [subtract both sides by 1]

x=-1

x+5=0 [subtract both sides by 5]

x=-5

Now, we have found three roots, x=0, x=-1, x=-5.

5 0

3 years ago