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1 year ago

4/5+8/9 (don’t mind this)

Mathematics

1 answer:

Basile [38]1 year ago

5 0

Answer:

Excact Form

76/45

Decimal Form

1.68 The 8 repeates itself

Mixed Number

1 31/45

Step-by-step explanation:

To add fractions, find the least common denominator and then combine

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Find the slope of the line that is perpendicular to y=-6x+12. PLEASE HURRYTTT

Alex17521 [72]

Answer:

m = -6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A) all values at which h has a local maximum <br> B ) all local maximum values of h

Harlamova29_29 [7]

For the given function h(x), we have:

a) at x = -2 and x = 2.

b) y = 0 and y = 3.

<h3>How to identify the maximums of function h(x)?</h3>

First, we want to get the values of x at which we have maximums. To do that, we need to see the value in the horizontal axis at where we have maximums.

By looking at the horizontal axis, we can see that the maximums are at:

x = -2 and at x = 2.

Now we want to get the maximum values, to do that, we need to look at the values in the vertical axis.

The first maximum value is at y = 0 (the one for x = -2)
The second maximum is at y = 3 (the one for x = 2).

If you want to learn more about maximums:

brainly.com/question/1938915

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4 0

1 year ago

DIscrete Math

Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

$f : X \rightarrow Y$ is surjective implies there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ .
If there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ , then $f : X \rightarrow Y$ is surjective

Let us start by the first implication.

Our hypothesis is that the function $f : X \rightarrow Y$ is surjective. From this we know that for every $y\in Y$ there exist, at least, one $x\in X$ such that $y=f(x)$ .

Now, define the sets $X_y = \{x\in X: y=f(x)\}$ . Notice that the set $X_y$ is the pre-image of the element $y$ . Also, from the fact that $f$ is a function we deduce that $X_{y_1}\cap X_{y_2}=\emptyset$ , and because $f$ the sets $X_y$ are no empty.

From each set $X_y$ choose only one element $x_y$ , and notice that $f(x_y)=y$ .

So, we can define the function $h:Y\rightarrow X$ as $h(y)=x_y$ . It is no difficult to conclude that $f\circ h(y) = f(x_y)=y$ . With this we have that $f\circ h=1_Y$ , and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function $h:Y\rightarrow X$ such that $f\circ h=1_Y$ .

Take an element $y\in Y$ , then $f\circ h(y)=y$ . Now, write $x=h(y)$ and notice that $x\in X$ . Also, with this we have that $f(x)=y$ .

So, for every element $y\in Y$ we have found that an element $x\in X$ (recall that $x=h(y)$ ) such that $y=f(x)$ , which is equivalent to the fact that $f$ is surjective. Therefore, the prove is complete.

3 0

2 years ago

Sean has some candy bars that he wants to give away. He is going to give each person \dfrac18 8 1 of a bar, and he has 2\dfrac

Dima020 [189]

Answer:

22 people

Step-by-step explanation:

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3 years ago

How much material is required to make a pipe that is 300 cm long whose outer diameter is 8 cm with an inner diameter of 5 cm? Sh

worty [1.4K]

Answer:

Step-by-step explanation:

If you had a solid cylinder, in order to find the amount of material that makes up that solid cylinder, you would find the volume using the radius of 4 (half of the diameter 8). BUT we want to know the volume of the solid with the radius of 4 minus the solid that has a radius of 2.5 (half of the diameter 5).

$V_o-V_i$ That's volume outer - volume inner. To find the outer volume: