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Sophie [7]
3 years ago
6

Given an angle, draw the opposite ray of one of its sides to form a linear pair. Find the measure of the angle formed by the ang

le bisector of the given angle and the drawn opposite ray if the measure of the given angle is: 50°, 90°, and 150°.
Mathematics
1 answer:
Andrej [43]3 years ago
4 0
<span>For 50°, answer is 65° For 90°, answer is 45° For 150°, answer is 15° A linear pair of angles adds up to 180° by definition. So the new angle drawn by the ray will have an angle of 180°-a where a is the measure of the original angle. And the bisector of that new angle will be (180°-a)/2. So with that in mind, let's calculate the new measures of the described construction. 50°: (18° - 50°)/2 = 130°/2 = 65° 90°: (180° - 90°)/2 = 90°/2 = 45° 150°: (180° - 150°)/2 = 30°/2 =15°</span>
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Consider a total of 1,000 people. If it was said that within 1 deviation (of the mean) of all people like MATH 123, how many of
Lesechka [4]

Answer:

680 students

Step-by-step explanation:

The 68 - 95 - 99.7  rule (empirical rule) states that 68% of the population lies within one standard deviation of the mean,  95% of the population lies within two standard deviations and 95% of the population lies within three standard deviations.

Hence since it was said that within 1 deviation (of the mean) of all people like MATH 123, therefore the number of people that like MATH 123 is:

number of people that like MATH 123 = 68% of the population

number of people that like MATH 123 = 0.68 * 1000

number of people that like MATH 123 = 680 students

3 0
3 years ago
Simplify the expression -3 devided by -2/5. A. -7 1/2 B. -1 1/5 C. 1 1/5 D. 7 1/2
Llana [10]

Answer:

D. 7 1/2

Step-by-step explanation:

-3 divided by -2/5

-(-3(-5/2)

-(-3 x 5/2)

-15/2

7 1/2

Hope it helps

7 0
3 years ago
Perform the division...please!​
____ [38]

Answer:

-7/3x + 3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a
katovenus [111]

1. Let a and b be coefficients such that

\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}

Combining the fractions on the right gives

\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}

\implies 1 = (2a+b)x + 3a

\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23

so that

\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}

2. a. The given ODE is separable as

x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}

Using the result of part (1), integrating both sides gives

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C

Given that y = 1 when x = 1, we find

\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)

so the particular solution to the ODE is

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)

We can solve this explicitly for y :

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)

\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|

\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|

\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}

2. b. When x = 9, we get

y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}

8 0
2 years ago
PLEASE HELP I WILL HELP YOU
Sidana [21]

Answer:

5 is the answer

Step-by-step explanation:

hope this helps

7 0
2 years ago
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