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Jlenok [28]
3 years ago
15

I REALLY NEED HELP ASAP

Mathematics
2 answers:
tiny-mole [99]3 years ago
4 0

FIRST PAGE: 20, 40, 20

SECOND PAGE: 15, 3, 6, 2 x 2 x 2 x 11

THIRD PAGE: 2 x 5 x 11

Veronika [31]3 years ago
3 0

<u>answer </u><u>#</u><u>1</u>

  • LCM of 4 and 5 = 20

<u>answer </u><u>#</u><u>2</u>

  • LCM of 5 and 8 = 40

<u>answer</u><u> </u><u>#</u><u>3</u>

LCM of 2, 4, and 5 = 20

<u>answer </u><u>#</u><u>4</u>

  • GCF of 15 and 60 = 60

<u>explanation</u><u> </u><u>#</u><u>4</u>

  • Factors of 15: 1, 3, 5, 15
  • Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

<u>answer </u><u>#</u><u>5</u>

  • GCF of 21, 24, and 27 = 3

<u>explanation</u><u> </u><u>#</u><u>5</u>

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Consider the parabola with a focus at the point (4,0) and directrix y = 3.
valentinak56 [21]

\sqrt{x^{2} + y^{2}-8x  +16} and mod(y-3)

Step-by-step explanation:

Step 1 :

Given the focus is at (4,0) and the directrix is y = 3. We have to find the 2 equations which relate the distance of the  given focus and the given directrix to any point (x, y) on the parabola

Step 2 :

The distance between a point P(x,y) given on the parabola and the focus (4,0)

is

\sqrt{(x-4)^{2} + (y-0)^{2} }  = \sqrt{x^{2}+16-8x + y^{2} } = \sqrt{x^{2} + y^{2}-8x  +16}

Step 3 :

The distance between the point P of (x,y) and the directrix line y = 3 is

mod (y-3)

So the 2 required equations are

\sqrt{x^{2} + y^{2}-8x  +16} and mod(y-3)

5 0
3 years ago
Can someone help me real quick
murzikaleks [220]

Hello!

  • Equation: y = 2.50x + 4
  • 7 rides.

We can write an expression to show this scenario. Write this in the equation format y = mx + b:

m = rate of change, or cost per ride

b = initial cost, or cost to enter the fair

y = 2.50x + 4

Solve for the amount of rides possible with $21.50:

21.50 = 2.50x + 4

Subtract 4 from both sides to isolate x:

17.50 = 2.50x

Divide both sides by 2.50:

17.50/2.50 = 7 rides.

7 0
3 years ago
12 of a number b increased by 7
Lilit [14]

Answer:

12b+7

Step-by-step explanation:

there's 12 of b and it increases by 7

7 0
3 years ago
When testing for current in a cable with eight ​color-coded wires, the author used a meter to test five wires at a time. How man
balu736 [363]

Answer:

56 different tests

Step-by-step explanation:

Given:

Number of wires available (n) = 8

Number of wires taken at a time for testing (r) = 5

In order to find the number of different tests required for every possible pairing of five wires, we need to find the combination rather than their permutation as order of wires doesn't disturb the testing.

So, finding the combination of 5 pairs of wires from a total of 8 wires is given as:

^nC_r=\frac{n!}{r!(n-r)!}

Plug in the given values and solve. This gives,

^8C_5=\frac{8!}{5!(8-5)!}\\\\^8C_5=\frac{8\times 7\times 6\times 5!}{5!\times 3\times2\times1}\\\\^8C_5=56

Therefore, 56 different tests are required for every possible pairing of five ​wires.

6 0
3 years ago
© Solve the simultaneous equations<br> -3x + y= – 8<br> 3x + 2y = – 13<br> X =?<br> y =?
DENIUS [597]

Answer:

x=1/3

y=-7

Step-by-step explanation:

using the elimination method, you can add both equations vertically, to eliminate the x

-3x+y=-8

3x+2y=-13

3y=-21

y=-7

we then fix the value of y into the first equation

-3x+y=-8

-3x-7=-8

-3x=-8+7

-3x=-1

x=1/3

5 0
3 years ago
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