2 years ago

Complete each statement to describe the relationship between gallons and liters.

1 answer:

6 0

Conversion
1 gallon = 3.785 liters

To convert gallons to liters multiply gallons by 3.785

1 liter= 0.264172 gallons

To convert liters to gallons multiply liters by 0.264172

3.78541 liters= 1 gallon

You might be interested in

A class has 4 boys and 10 girls. What is the ratio in the simplest form that compares a number of boys to a total number of stud

sergejj [24]

Answer:

4 to 14 should be the right answer

6 0

3 years ago

A purchaser paid $1,539.13 for a computer system that originally cost $1,215.91. If the markup was 21% of the $1,539.13 selling

liubo4ka [24]

Answer:

$1272.008264

Step-by-step explanation:

If the mark-up was 21%, then the final price is 121% of the original price. Simply divide $1,539.13 by 1.21 to get the original price of $1272.008264

7 0

4 years ago

At the beginning of the month, Sheryl had a balance of $120 in her checking account. She then made a purchase for $80, using her

Rama09 [41]

$80

add what you took out

3 0

3 years ago

Danessa needs to compare the area of one large circle with a diameter of 8 to the total area of 2 smaller circles with a diamete

BaLLatris [955]

Answer:

The answer is: 1, 2, and 6

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

3 years ago